Solving Linear Equations and Inequalities

Solving Linear Equations and Inequalities

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial guides viewers through solving a complex equation involving fractions. It begins by introducing the equation and then demonstrates how to simplify it by removing terms and simplifying fractions. The tutorial continues by isolating the variable K and solving for it, ultimately finding that K equals zero. The solution is verified by substituting back into the original equation, confirming the correctness of the solution.

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18 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial equation presented in the video?

17K + 28 / 21 + 4/3 = 0

17K - 28 / 21 - 4/3 = 0

17K + 28 / 21 - 4/3 = 0

17K - 28 / 21 + 4/3 = 0

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in simplifying the equation?

Multiply both sides by 21

Subtract 4/3 from both sides

Add 4/3 to both sides

Divide both sides by 21

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

After subtracting 4/3 from both sides, what does the equation become?

17K + 28 / 21 = 4/3

17K - 28 / 21 = 4/3

17K - 28 / 21 = -4/3

17K + 28 / 21 = -4/3

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What operation is used to eliminate the fraction in the equation?

Divide both sides by 21

Multiply both sides by 21

Subtract 21 from both sides

Add 21 to both sides

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the purpose of multiplying both sides by 21?

To eliminate the fraction

To add a constant

To divide the equation

To subtract a constant

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of multiplying -4/3 by 21?

-28

28

-7

7

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the fraction -4/3 simplified when multiplied by 21?

By dividing both numerator and denominator by 7

By multiplying both numerator and denominator by 7

By dividing both numerator and denominator by 3

By multiplying both numerator and denominator by 3

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