Solving Linear Equations and Substitution

In Algebra 1 Lesson 59, the focus is on rearranging equations before substitution. The lesson demonstrates solving two problems using substitution to find the values of x and y. The instructor guides through the process of isolating variables, applying the distributive property, and solving equations step-by-step. The lesson concludes with a recap and encourages students to practice the method.

What is the main focus of Algebra 1 Lesson 59?

• Graphing linear equations

• Factoring polynomials

• Rearranging before substitution

• Solving quadratic equations

In the first problem, what is the initial equation given?

• x + 2y = 1

• x - 2y = 1

• 3x + y = 5

• 2x - 3y = 4

What is the first step in solving for x in the equation x - 2y = 1?

• Add 2y to both sides

• Subtract 1 from both sides

• Multiply both sides by 2

• Divide both sides by x

After rearranging the equation x - 2y = 1, what does x equal?

• x = 1 - 2y

• x = 2y - 1

• x = -1 + 2y

• x = 2y + 1

What is the next step after finding x = -1 + 2y?

• Check the solution

• Substitute x into another equation

• Graph the equation

• Solve for y in the same equation

In the equation 2x - 3y = 4, what do you substitute for x?

• 3y + 1

• -1 + 2y

• 1 - 2y

• 2y - 1

What is the value of y after solving the equation 2(-1 + 2y) - 3y = 4?

• y = 6

• y = 7

• y = 4

• y = 5

After finding y = 6, what is the next step?

• Substitute y back into the original equation

• Solve for x in a new equation

• Graph the solution

• Check the solution

What is the value of x when y = 6 in the equation x - 2y = 1?

• x = 9

• x = 10

• x = 11

• x = 12

How is the solution written as a coordinate pair?

• (10, 5)

• (5, 10)

• (11, 6)

• (6, 11)