Conic Sections and Rotating Axes

Conic Sections and Rotating Axes

Assessment

Interactive Video

Mathematics

11th - 12th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to rotate axes to eliminate the xy term in a conic equation. It begins by introducing the standard form of a conic and the need for rotation. The angle of rotation, theta, is calculated using the cotangent formula. The tutorial then uses triangles and the Pythagorean theorem to find sine and cosine values. These values are used to convert coefficients to a new coordinate system, resulting in a new equation in the rotated x' y' coordinates.

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7 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the primary goal of rotating the axes in the context of conic sections?

To simplify the equation by removing the xy term

To change the shape of the conic

To make the equation more complex

To increase the number of terms in the equation

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the standard form of a conic section, what does the term 'bxy' represent?

The mixed term

The quadratic term

The constant term

The linear term

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the angle of rotation θ determined in the context of conic sections?

By using the cosine formula

By using the tangent formula

By using the cotangent formula

By using the sine formula

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In which quadrant is the angle 2θ located if its cotangent is negative?

First quadrant

Second quadrant

Fourth quadrant

Third quadrant

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which trigonometric identity is used to find the sine of θ?

Pythagorean identity

Sine double angle identity

Half angle identity

Cosine double angle identity

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of a' after the rotation of axes?

3

-7

1

0

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the final form of the conic equation in the rotated coordinate system?

3x'^2 + 7y'^2 - (1/√5)x' - (8/√5)y' + 2 = 0

3x'^2 - 7y'^2 - (1/√5)x' - (8/√5)y' + 2 = 0

3x'^2 - 7y'^2 + (1/√5)x' + (8/√5)y' + 2 = 0

3x'^2 + 7y'^2 + (1/√5)x' + (8/√5)y' + 2 = 0