Rectangle Area and Dimensions Problems

The video tutorial covers solving word problems involving rectangles using algebra. It begins with a problem where the length of a rectangle is 1 cm less than twice its width, and the area is 45 square cm. The solution involves setting up a quadratic equation and factoring it to find the dimensions. The second problem involves a rectangle with an area of 33 square meters, where the length is 2 meters more than three times the width. Again, a quadratic equation is used to find the dimensions. The tutorial emphasizes understanding the relationship between length, width, and area, and solving quadratic equations through factoring.

What is the main focus of the video tutorial?

• Solving word problems involving circles

• Solving word problems involving rectangles

• Solving word problems involving triangles

• Solving word problems involving squares

How is the length of the rectangle related to its width?

• The length is twice the width plus one

• The length is twice the width minus one

• The length is half the width minus one

• The length is half the width plus one

What is the area of the rectangle in the first problem?

• 40 square cm

• 50 square cm

• 45 square cm

• 35 square cm

What type of equation is used to solve for the width of the rectangle?

• Linear equation

• Quadratic equation

• Cubic equation

• Exponential equation

What are the dimensions of the rectangle after solving the equation?

• Length = 7, Width = 5

• Length = 8, Width = 6

• Length = 9, Width = 5

• Length = 10, Width = 4

What is the area of the rectangle in the second problem?

• 40 square m

• 30 square m

• 33 square m

• 35 square m

How is the length of the rectangle related to its width in the second problem?

• The length is three times the width plus two

• The length is three times the width minus two

• The length is twice the width plus two

• The length is twice the width minus two

What is the quadratic equation used in the second problem?

• 0 = 3w^2 - 2w - 33

• 0 = 2w^2 - 3w - 33

• 0 = 2w^2 + 3w - 33

• 0 = 3w^2 + 2w - 33

What are the dimensions of the rectangle in the second problem?

• Length = 9, Width = 3

• Length = 12, Width = 5

• Length = 11, Width = 3

• Length = 10, Width = 4