Basic Arithmetic and Word Problems

Basic Arithmetic and Word Problems

Assessment

Interactive Video

•

Mathematics

•

9th - 10th Grade

•

Practice Problem

•

Hard

Created by

Thomas White

FREE Resource

The video tutorial covers solving equations with fractions and special cases, emphasizing a method to handle fractions by finding a common denominator or distributing. It also explains solving a word problem involving the phrase 'less than', highlighting the importance of reversing terms when using 'less than'. The tutorial provides step-by-step guidance on these mathematical concepts.

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34 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving an equation with variables on both sides?

Divide both sides by a common factor

Multiply both sides by a common factor

Subtract the variables from both sides

Add the variables together

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

When dealing with fractions, what is one method to simplify the equation?

Multiply the fractions by zero

Ignore the fractions

Add the fractions directly

Find a common denominator

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In a special case where both sides of an equation are identical, what is the solution?

Only positive numbers

Only negative numbers

All real numbers

No solution

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the word 'less than' indicate in a word problem?

Division

Subtraction

Addition

Multiplication

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the result of multiplying 1/2 by 36?

18

72

36

9

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the phrase '15 less than twice a number', where does the 15 go?

In the middle of the equation

At the end of the equation

It is not used

In front of the equation

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the solution to the equation 2x - 15 = x + 2?

x = 21

x = 19

x = 17

x = 15

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