Quadratic Equations and Discriminants

Quadratic Equations and Discriminants

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

This video tutorial covers solving quadratic equations with a focus on finding conditions for equal roots. It begins with a recap of the discriminant and its role in determining root nature. The tutorial then solves problems to find values of constants that result in equal roots, explores the relationship between coefficients for equal roots, and calculates a constant when specific roots are given.

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36 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the discriminant of a quadratic equation used for?

To determine the nature of the roots

To solve linear equations

To find the sum of the roots

To calculate the product of the roots

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which of the following indicates that a quadratic equation has equal roots?

Discriminant is less than zero

Discriminant is a perfect square

Discriminant is greater than zero

Discriminant is equal to zero

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the discriminant of a quadratic equation is negative, what can be said about its roots?

The roots are complex

The roots are integers

The roots are real and equal

The roots are real and distinct

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the roots of a quadratic equation are equal, what is the value of the discriminant?

Greater than zero

Undefined

Less than zero

Equal to zero

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

If the roots of a quadratic equation are real and distinct, what can be said about the discriminant?

It is equal to zero

It is less than zero

It is undefined

It is greater than zero

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

In the equation x^2 - (k + 1)x + 5k - 19 = 0, what is the value of 'a'?

0

1

5k - 19

k + 1

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

For the equation x^2 - (k + 1)x + 5k - 19 = 0, what is the value of 'b'?

1

0

k + 1

5k - 19

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