Understanding Annulus and Its Properties

Understanding Annulus and Its Properties

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains the concept of an annulus, which is the region between two concentric circles. It details how to calculate the area of an annulus by subtracting the area of the smaller circle from the area of the larger circle. The tutorial provides a step-by-step guide to derive the formula for the area of an annulus, emphasizing the importance of knowing the radii of both circles involved.

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15 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is an annulus?

A square inside a circle

A region between two circles

A single circle

A triangle inside a circle

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the annulus defined in terms of circles?

As a single circle

As a region outside a circle

As the area between two circles

As a line inside a circle

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What are the two circles involved in forming an annulus?

Two larger circles

Two identical circles

A larger outer circle and a smaller inner circle

Two smaller circles

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the larger circle in an annulus?

It is irrelevant

It determines the outer boundary

It is inside the smaller circle

It is the same as the smaller circle

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the smaller circle in an annulus?

It is outside the larger circle

It is the same as the larger circle

It determines the inner boundary

It is irrelevant

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How do you calculate the area of an annulus?

Add the areas of two circles

Subtract the area of the smaller circle from the larger circle

Divide the area of the larger circle by the smaller circle

Multiply the areas of two circles

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the area of an annulus?

π * (R^2 - r^2)

π * (R - r)

π * (R^2 + r^2)

π * (R + r)

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