Analyzing Polar Curves and Areas

Analyzing Polar Curves and Areas

Assessment

Interactive Video

Mathematics

11th - 12th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to find the area of the curve defined by the equation r^2 = a^2 cos(2θ). It discusses the symmetry properties of the curve, showing that it is symmetric about the line θ = π/2 and the initial line. The tutorial transforms the equation to identify real portions of the curve and explains the formation of loops due to symmetry. Finally, it calculates the area enclosed by the curve using integration, considering the symmetry to simplify the process.

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12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main objective of the video tutorial?

To solve a quadratic equation

To learn about trigonometric identities

To find the area of a rectangle

To find the area of the curve r² = a² cos(2θ)

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which equation is used to find the area of the curve?

A = 1/3 ∫ r² dθ

A = l × w

A = πr²

A = 1/2 ∫ r² dθ

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What happens to the equation when θ is replaced by -θ?

The equation changes completely

The equation remains unchanged

The equation becomes undefined

The equation doubles

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the significance of the power of r being 2 in the equation?

It makes the equation linear

It ensures the equation is always positive

It allows symmetry about the line θ = π/2

It makes the equation quadratic

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the derived equation from r² = a² cos(2θ)?

r² = a² sin(2θ)

r²/a² = cos(2θ)

r² = a² tan(2θ)

r²/a² = sin(2θ)

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the range of θ for which cos(2θ) is non-negative?

0 ≤ θ ≤ π/2

π/2 ≤ θ ≤ π

0 ≤ θ ≤ π/4

π/4 ≤ θ ≤ π/2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Between which values of θ does the curve have a real portion?

θ = 0 and θ = π/2

θ = 0 and θ = π/4

θ = π/2 and θ = π

θ = π/4 and θ = π/2

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