
Graphing Functions and Transformations

Interactive Video
•
Mathematics
•
9th - 10th Grade
•
Hard

Thomas White
FREE Resource
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8 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What was the initial task given to Alex in the video?
To find the derivative of G(x).
To solve an equation involving F(x).
To graph F(x) and G(x) and analyze the transformation.
To compare F(x) with a constant function.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step Alex took to solve the problem?
He calculated the derivative of F(x).
He compared F(x) with G(x) directly.
He graphed the function F(x).
He solved for the roots of F(x).
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What transformation was observed from F(x) to G(x)?
Vertical stretch
Horizontal compression
Translation to the right
Reflection over the x-axis
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What was Gabby's task in the video?
To find the derivative of K(x).
To solve an equation involving H(x).
To compare H(x) with a constant function.
To graph H(x) and K(x) and analyze the transformation.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step Gabby took to solve her problem?
She calculated the derivative of H(x).
She graphed the function H(x).
She compared H(x) with K(x) directly.
She solved for the roots of H(x).
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What transformation was observed from H(x) to K(x)?
Translation to the left
Vertical compression
Horizontal stretch
Reflection over the y-axis
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How did Gabby manipulate the second function to demonstrate the horizontal stretch?
By multiplying the function by a constant.
By adding a constant to the function.
By changing the base of the exponent.
By reflecting it over the x-axis.
8.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the effect of a horizontal stretch on the rate of increase of a function?
It increases the rate of increase.
It decreases the rate of increase.
It has no effect on the rate of increase.
It makes the function constant.
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