Finding Quadratic Equations from Points

Finding Quadratic Equations from Points

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

In this video, Adele Kumar explains how to derive a quadratic equation from three given points on a parabola. The video begins with an introduction to the problem, identifying the y-intercept and other points on the parabola. It then demonstrates how to formulate equations using these points and solve for the unknown coefficients. The final quadratic equation is derived, and the process is summarized, providing a clear understanding of how to find a quadratic equation from given points.

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19 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the main objective of the video tutorial?

To understand the properties of a circle

To learn how to solve linear equations

To explore the concept of derivatives

To write a quadratic equation from three given points

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general form of a quadratic equation?

y = ax^2 + bx + c

y = mx + c

y = a/x + b

y = ax^3 + bx^2 + cx + d

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the y-intercept of a parabola?

The point where the parabola crosses the x-axis

The point where the parabola crosses the y-axis

The vertex of the parabola

The focus of the parabola

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the value of C determined in the quadratic equation?

By using the focus of the parabola

By using the vertex of the parabola

By substituting the x-intercept

By substituting the y-intercept

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the value of C in the given problem?

2

4

0

-4

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which point is used to form the second equation involving A and B?

The second given point

The y-intercept

The vertex of the parabola

The focus of the parabola

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the equation formed using the second point?

8 = 3a - 2b

12 = 4a - 2b

4 = a + b

6 = 2a - b

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