Logarithms and Exponential Equations

Logarithms and Exponential Equations

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Hard

Created by

Thomas White

FREE Resource

The video tutorial explains how to solve equations involving exponents by isolating the exponent and applying logarithms. It discusses the limitations of calculators that only support log base 10 and introduces the change of base formula to overcome this. The tutorial concludes by solving for X using these methods.

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10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the first step in solving an equation with an exponent?

Add a constant to both sides

Isolate the exponent

Multiply both sides by the base

Take the square root of both sides

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Why can't the one-to-one property be used in this scenario?

The bases are not the same

The exponents are too large

The equation is not balanced

The bases are negative

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the next step after determining the one-to-one property cannot be used?

Add a constant to both sides

Take the logarithm of both sides

Multiply both sides by the base

Divide both sides by the exponent

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Which logarithm base is chosen to solve the equation?

Base 5

Base 2

Base 10

Base 3

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is a limitation of most scientific calculators regarding logarithms?

They cannot calculate any logs

They can only calculate log base 10

They can only calculate log base 2

They can only calculate natural logs

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What formula is used to calculate logarithms with a different base?

Pythagorean theorem

Exponential growth formula

Change of base formula

Quadratic formula

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the change of base formula applied in this scenario?

By multiplying log base 10 of 7 by log base 10 of 3

By dividing log base 10 of 7 by log base 10 of 3

By subtracting log base 10 of 3 from log base 10 of 7

By adding log base 10 of 7 to log base 10 of 3

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