Mixture and Concentration Problem Quiz

Mixture and Concentration Problem Quiz

Assessment

Interactive Video

Mathematics

9th - 10th Grade

Practice Problem

Hard

Created by

Nancy Jackson

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the initial condition of the tank before the saltwater solution is added?

The tank is empty.

The tank contains 100 gallons of saltwater.

The tank contains 100 gallons of pure water.

The tank contains 50 gallons of pure water.

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What does the variable 'A' represent in the context of this problem?

The rate of water entering the tank.

The rate of salt leaving the tank.

The amount of salt in the tank at time T.

The amount of water in the tank.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

How is the rate of salt entering the tank calculated?

By subtracting 4% from the rate of 2 gallons per minute.

By dividing 4% by the rate of 2 gallons per minute.

By adding 4% to the rate of 2 gallons per minute.

By multiplying 4% by the rate of 2 gallons per minute.

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the formula for the rate of salt leaving the tank?

A plus 100 times 2 gallons per minute.

A minus 100 divided by 2 gallons per minute.

A divided by 100 times 2 gallons per minute.

A times 100 divided by 2 gallons per minute.

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the differential equation that represents the rate of change of salt in the tank?

da/dt = 0.02A - 0.08

da/dt = 0.08 - 0.02A

da/dt = 0.08 + 0.02A

da/dt = 0.02A + 0.08

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the integrating factor used to solve the differential equation?

e to the integral of 0.04

e to the integral of 0.08

e to the integral of 0.06

e to the integral of 0.02

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the general solution of the differential equation before applying the initial condition?

A = 4 - C e^(0.02T)

A = 4 - C e^(-0.02T)

A = 4 + C e^(0.02T)

A = 4 + C e^(-0.02T)

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