
Understanding Real Gases and the Van der Waals Equation

Interactive Video
•
Chemistry
•
11th - 12th Grade
•
Hard
Nancy Jackson
FREE Resource
10 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the primary difference between real gases and ideal gases?
Real gases do not exist, while ideal gases do.
Real gases have no volume, unlike ideal gases.
Real gases follow the ideal gas law under all conditions.
Real gases exhibit interactions between molecules, unlike ideal gases.
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
In a graph of real gases, what does it indicate when the compressibility factor is below the ideal gas line?
Attractive forces are dominant.
The gas is at a very high pressure.
The gas is behaving ideally.
Repulsive forces are dominant.
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What happens to the compressibility factor of a real gas at very high pressures?
It decreases below one.
It remains constant.
It equals zero.
It increases above one.
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What does the 'a' constant in the Van der Waals equation account for?
The pressure of the gas.
The temperature of the gas.
The volume of the gas molecules.
The attractive forces between molecules.
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
Which of the following is true about the Van der Waals equation compared to the ideal gas law?
It is simpler to use than the ideal gas law.
It includes terms for molecular interactions.
It does not account for molecular volume.
It is less accurate at high pressures.
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the significance of the 'b' constant in the Van der Waals equation?
It is used to calculate temperature.
It accounts for the volume occupied by gas molecules.
It represents the ideal gas constant.
It accounts for the attractive forces.
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
How does the Van der Waals equation adjust the ideal gas law?
By removing the volume term.
By including terms for molecular volume and attraction.
By adding a term for temperature.
By subtracting a term for pressure.
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