Hydrobromination of Alkenes with Peroxide Quiz

What is the main difference between anti-Markovnikov and Markovnikov addition in hydrobromination?

• Anti-Markovnikov places bromine on the more substituted carbon.

• Anti-Markovnikov places bromine on the less substituted carbon.

• Markovnikov addition does not involve HBr.

• Markovnikov addition involves peroxide.

In the mechanism of hydrobromination with peroxide, what is the first species to react with the alkene?

• Bromine radical

• Hydrogen radical

• Carbocation

• Peroxide

What is the role of the bromine radical in the propagation steps?

• It initiates the reaction.

• It terminates the reaction.

• It forms a bond with the more substituted carbon.

• It reacts with the alkene to form a stable intermediate.

During the propagation steps, what happens to the radical concentration?

• It fluctuates.

• It increases.

• It decreases.

• It remains constant.

What is the purpose of the peroxide in the initiation steps?

• To form a stable carbocation.

• To break the oxygen-oxygen bond and form radicals.

• To terminate the reaction.

• To directly react with the alkene.

How many initiation steps are involved in this reaction mechanism?

• One

• Two

• Three

• Four

What is a characteristic of a termination step in this reaction?

• It increases the concentration of radicals.

• It involves peroxide.

• It forms the desired product.

• It forms side products.

Which of the following is a possible termination step?

• Formation of a bromine radical.

• Formation of a stable carbocation.

• Formation of a new carbon-carbon bond.

• Formation of a peroxide radical.

What happens to the bromine radicals during termination?

• They form HBr.

• They react with peroxide.

• They form Br2.

• They form a stable alkene.

Why are alkoxide radicals usually ignored in termination steps?

• They are present in high concentration.

• They are too reactive.

• They are present in low concentration.

• They do not form any products.