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Genetics Review

Total questions: 9

Worksheet time: 24mins

Name
Class
Date
1.
Purple flowers are dominant to white flowers.
What is the phenotype of the flower whose genotype is Pp
a)
white
b)
purple
c)
lilac 
d)
spotted 
2.
In dogs, the gene for fur color has two alleles.  The dominant allele (F) codes for grey fur and the recessive allele (f) codes for black fur. The female dog is heterozygous.  The male dog is homozygous recessive. Predict  the most likely  phenotype ratio and  and genotype ratio  of their possible puppies. 
a)
100% black ff
b)
100% grey FF
c)
50% grey Ff
d)
25% grey FF
3.
In some chickens, the gene for feather color is controlled by codominance. The allele for black is B and the allele for white is W. The heterozygous phenotype is known as erminette. What is the genotype for erminette chickens? 
a)
BB
b)
FwFw
c)
WW
d)
FWFB
4.

If two erminette (heterozygous) chickens were crossed, what is the probability that they would have a black chick? ____%

a)

0%

b)

25%

c)

50%

d)

100%

5.
The father has blood type A heterozygous, the mother is type B homozygous. What is the probability of the offspring having type O blood? 
a)
0%
b)
25%
c)
50%
d)
100%
6.

Alice has type A blood. Her first child, Amanda, has type O blood. Her second child, Alex, has type AB blood. What is the husbands genotype?

a)

ii

b)

IBIB

c)

IBi

d)

IAIB

7.
In Andalusian fowls, black individuals (BB) and white individuals (WW) are homozygous.   Heterozygous offspring are all bluish-gray.   What results if a black individual is crossed with a bluish-gray individual? 
a)
0% black
b)
0% white
c)
0% blue grey
d)
100% black 
8.
  In humans, hemophilia is a sex linked trait. What is the genotype of a women who is a carrier?    
a)
Hh
b)
XHXh
c)
XHYh
d)
HH
9.
Cross a man who has hemophilia with a woman who is a carrier. What is the probability that their children will have the disease? 
a)
0%
b)
25%
c)
50%
d)
100%