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WorksheetsLG 22 Practice Quiz (Exponential Functions and Transformations)
Total questions: 17
Worksheet time: 4hrs 15mins
What is the y-intercept of the function?
A
(0,2)
B
(0,3)
C
(0,1)
D
(0,-2)
This graph represents:
A
Exponential Growth
B
Exponential Decay
C
Direct Variation
D
None of the above
Is the pictured graph growth, decay, or linear?
A
Exponential Growth
B
Exponential Decay
C
Linear
D
None of the above
What is the range of this graph?
A
y = 6
B
(0, -4)
C
y > -6
D
y < -6
The point (1,0) is:
A
a zero
B
the y-intercept
C
the domain
D
the range
What type of function is:
f(x) = 7(5/4)x?
A
Exponential Growth
B
Exponential Decay
C
Linear
D
None of the above
Which equation matches the graph?
A
f(x) = 2(2)x
B
f(x) = 2(1/2)x
C
f(x) = 2x
D
f(x) = 1/2(2)x
What kind of shift is represented?
f(x) = 2x-1
A
up 1 unit
B
left 1 unit
C
right 1 unit
D
down 1 unit
What is the asymptote value in the function?
f(x) = 3(7)x + 2
A
y = 3
B
y = 2
C
x = 3
D
x = 2
What does a in
y=a(1+r)x
represent?
A
Time
B
Rate
C
Slope
D
Initial Amount
What is the horizontal asymptote and what transformations have taken place?
y = 2x+2 + 1
A) y = 2
right 2, up 1
B) y = 1
left 2, up 1
C) y = 1
right 2, up 1
D) y = 2
right 1, up 2
What transformations have happened to y = 2x if the new equation is
y = -2(x+3) -6
A
It stayed the same
B
flips, up 3, left 6
C
flips, right 3, down 6
D
flips, left 3, down 6
The function:
f(x) = 500 (2)x
represents the growth of bacteria over a 5 day period. What is an appropriate Domain for this function?
A
0 ≤ X < ∞
B
0 ≤ x ≤ 5
C
500 ≤ x ≤ 16,000
D
500 ≤ x ≤ ∞
The function:
f(x) = 500 (2)x
represents the growth of bacteria over a 5 day period. What is an appropriate Range for this function?
A
0 ≤ y < ∞
B
0 ≤ y ≤ 5
C
500 ≤ y 16,000
D
500 ≤ y < ∞
f(x) = a(b)x
If b = 0.5, the function represents
A
linear
B
growth
C
quadratic
D
decay
Which exponential function passes through the points:
(4, 1536) & (2 , 96)
A
f(x) = 4 ⋅ (6x)
B
f(x) = 6⋅ (1/4x)
C
f(x) = 4 ⋅ (6x) - 3
D
f(x) = 6 ⋅ (4x)
Which function is represented in the graph?
A
f(x) = 3⋅ (1/4x) - 5
B
f(x) = -2⋅ (1/4x) - 5
C
f(x) = 3⋅ (4x) - 5
D
f(x) = 3⋅ (4x) + 5
