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WorksheetsCalculus Final Review
Total questions: 75
Worksheet time: 3hrs 36mins
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Find the derivative. f(x) = -8x-3 + 5x - e2
f'(x) = -24x-4 + 5 - ex-1
f'(x) = 24x-4 + 5
f'(x) = 24x-2 + 5
f'(x) = 24x-4 + 5 - e
find f'(x)
f'(x)=
g'(x)=
dy/dx =
y=√x
y'=
√x
1/√x
1/(2√x)
-1/(2√x)
f'(x) =
f'(x) =
y'=
y'=
The formal definition of a derivative is:
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If c is a critical number then f(c) is either a local maximum or a local minimum
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The x value where the 2nd derivative is equal to zero is commonly referred to as a "critical point".
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If the 2nd derivative of a function is negative on that interval, then that interval is concave down.
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If the first derivative of a function changes from positive to negative at a certain point, then that point is a known as a relative minimum.
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When do you use the chain rule?
anytime you want
when there is a function in a function
where there are multiple layers
when there is division
-135
-5/27
-5/729
-5
f(x) = (5x5 + 5)2
