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WorksheetsExponential and Logarithmic Mathematical Model
Total questions: 11
Worksheet time: 17mins
The population of a country is 50 millions of inhabitants. If it grows exponentially in a rate of 2% per year, calculate the estimated population in 15 years
1.02 million people
6 years
3.5 years
67.3 million people
2%
The population of a country is 50 millions of inhabitants. If it grows exponentially in a rate of 2% per year, calculate: In how long is it estimated that the population will be 82.5 million?
1.02 millions
35 years
(1.2)x
10 years
25.3 years
The population of a country is 50 million of inhabitants. If it grows exponentially in a rate of 2% per year, calculate: The time of duplication
17.3 hours
35 years
17.3 seconds
6 years
1.02 millions
The population of a country is 50 million of inhabitants. If it grows exponentially in a rate of 2% per year, calculate the time of quadruplication.
70 years
63.7 millions
17.3 seconds
5 seconds
5 hours
The census of 1990 showed that the population in millions of inhabitants of certain city were 2.374 millions, while in the year 2000 the population was 3.19 millions. If the population grows exponentially with time, find what the estimated population was in the year 2007
2015
3.92 million people
1.02998523 million people
2.37410
year 2012
The census of 1990 showed that the population in millions of inhabitants of certain city were 2.374 millions, while in the year 2000 the population was 3.19 millions. If the population grows exponentially with time, find: In what year the city will have 5.765 of inhabitants?
2000
2013
1990
1.02998523 million people
2020
Graph of an exponential function with factor of decay 0<b<1
Graph of an exponential function with a growth factor b>1
Calculate the pH of a substance if [H+]= 2.4 x 10-3 considering that pH= - log[H+]
2.4
ln
-3
2.61
hydrogen
The number of bacteria (n) present in a culture liquid after t hours of proliferation is determined by the expression n=12000(2)t/2 find: The number of bacteria after 8 hours of proliferation
log(n)
2
12,000 bacteria
30 days
192,000 bacteria
The number of bacteria (n) present in a culture liquid after t hours of proliferation is determined by the expression n=12000(2)t/2 find: After how long will bacteria duplicate their population.
30 days
12,000
3 hours
log(n)
ln(n)
