Free Printable phy_2.9_circular motion 圓周運動 1

1.

計算線距離 s 的公式是
The equation for calculating the linear distance s is

a)

$s=2\pi r$

b)

$s=r\theta$

c)

$s=\frac{\theta}{t}$

d)

$s=r\omega$

2.

轉一圈的角距離 $\theta$ 是多少?
What is the angular distance $\theta$ for one revolution?

a)

$1\pi$ rad

b)

$2\pi$ rad

c)

360 rad

d)

180 rad

3.

物體作勻速圓周運動時，它的週期 T

When an object performs uniform circular motion, its period T

a)

是它移動方向逆轉一次所需的時間。

indicates the time taken for the moving direction of the object to reverse.

b)

是它停下所需的時間。

indicates the time taken for the object to stop.

c)

是它旋轉一周所需的時間。

indicates the time taken for the object to complete one revolution.

d)

只與它的線速率有關。

is only related to the linear speed of the object.

4.

每秒轉 0.5 週，其週期 T = ?

0.5 revolutions per second, its period T = ?

a)

0.5 s

b)

5 s

c)

0.2 s

d)

2 s

5.

每秒轉 0.5 週，角速率 $\omega$ =？
0.5 revolution per second, angular speed $\omega$ = ?

a)

1 rad s-1

b)

2 rad s-1

c)

$\pi$ rad s-1

d)

$2\pi$ rad s-1

6.

求地球自轉的角速率 $\omega$ 。
Find the angular speed of the earth's rotation $\omega$ 。

a)

$2\pi\ rad\ s^{-1}$

b)

$\frac{2\pi}{24}\ rad\ s^{-1}$

c)

$\frac{2\pi}{24\times60\times60}\ rad\ s^{-1}$

d)

$=\frac{2\pi}{60}\ rad\ s^{-1}$

7.

計算線速率 v 的公式是
The equation for calculating the linear speed v is

a)

$v=r\theta$

b)

$v=2\pi r$

c)

$v=r\omega$

d)

$v=\frac{\theta}{t}$

8.

一輛單車以 0.5 rad s^-1的角速率沿著圓形路徑行駛。已知圓形路徑的半徑為 30 m，單車的線速率 v 是多少？
A bicycle travels along a circular track of radius 30 m at a angular speed of 0.5 rad s-1. What is its linear speed v?

a)

15 m s-1

b)

30 m s-1

c)

45 m s-1

d)

60 m s-1

9.

一輛單車以 10 m s^-1的恆速率沿著圓形路徑行駛。已知圓形路徑的半徑為 40 m，單車的角速率 $\omega$ 是多少？
A bicycle travels along a circular track of radius 40 m at a constant speed of 10 m s-1. What is its angular speed $\omega$ ?

a)

0.25 rad s-1

b)

4 rad s–1

c)

25 rad s–1

d)

400 rad s–1

10.

一輛單車以 10 m s^-1的恆速率沿著圓形路徑行駛。已知圓形路徑的半徑為 40 m，單車的週期 T 是多少？
A bicycle travels along a circular track of radius 40 m at a constant speed of 10 m s-1. What is the period T of the bicycle?

a)

$\frac{2\pi\times10}{40}\ s$

b)

$\frac{2\pi\times40}{10}\ s$

c)

$\frac{10}{2\pi\times40}\ s$

d)

$\frac{40}{2\pi\times10}\ s$

phy_2.9_circular motion 圓周運動 1

Total questions: 10

Worksheet time: 3hrs 30mins

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