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WorksheetsLogs & Exponentials
Total questions: 17
Worksheet time: 1hrs 25mins
Rewrite as an exponential: log28 = 3
32 = 8
23 = 8
28 = 3
83 = 2
Rewrite as an exponential: log7(491)=−2
7491=−2
(491)−2=7
7−2=491
(−2)7=491
Rewrite as an exponential: log93=21
921=3
321=9
93=21
(21)9=3
Rewrite as a log: y = 7x
log7(x) = y
logy(7) = x
logx(y) = 7
log7(y) = x
Rewrite as a log: x = 11y
log11(y) = x
logy(11) = x
log11(x) = y
logx(y) = 11
Rewrite as a log: 70 = 1
log7(1) = 0
log0(7) = 1
log7(0) = 1
log1(0) = 7
What is the base for the following log:
y = log (x)
1
0
10
2
Find x: log2(32) = x
x = 5
x = 16
x = 4
x = 6
Find x: log5(x) = 4
x = 20
x = 25
x = 625
x = 125
Find x: logx(25) = 2
x = 1
x = 12.5
No Solution
x = 5
Find x: log7(71)=x
x = -1
x = 1
x = 0
No Solution
Find x: log5(x) = 0
No Solution
x = 0
x = 5
x = 1
Find x: logx(81)=−3
x = 2
x = -2
x = 2.67
No Solution
Find the exponential equation that represents the table.
y = 2(3)x
y = 3 + (3)x
y = 3(2)x
y = 6(2)x
Find the equation of the exponential function that passes through the points (2, 1) and (4, 0.25).
y = 0.25(2)x
y = 4(0.5)x
y = 1(0.5)x
y = 0.5(2)x
Find the equation of the exponential function that passes through the points (1, 12) and (4, 768).
y = 12(4)x
y = 1.5(8)x
y = 3(4)x
y = 1.33(9)x
A chemical substance has a half-life of 3 days. If you start with 90 grams of the substance, how much will be left after 13 days? Write an equation to help you find your answer.
about 4.487 grams
about 0.011 grams
about 0.9924 grams
about 4.221 grams
