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Unit 1 Review

Total questions: 18

Worksheet time: 12mins

Name
Class
Date
1.

Change in position ( Δx\Delta x  )

a)

distance

b)

displacement

c)

speed

d)

velocity

2.

Numbers that give both a magnitude and a direction

a)

Scalar

b)

Vector

c)

Normal

d)

Irregular

3.

If you know the components of a vector, you can solve for which of the following?

a)

Magnitude

b)

Scalar

c)

Angle

d)

Length along the X Axis

e)

Length along the Y Axis

4.

If you know the length of the hypotenuse of a right triangle, what do you know about its vector?

a)

The magnitude

b)

The angle

c)

The X component

d)

The Y component

5.

What does the symbol θ\theta  represent?

a)

The magnitude of a vector

b)

The angle of a vector

c)

The magnitude of a scalar

d)

The angle of a scalar

6.

When you divide change in velocity by change in time, what do you get?

a)

Displacement

b)

Distance

c)

Acceleration

d)

Velocity

7.

If you graph position/time, what is the slope?

a)

Acceleration

b)

Displacement

c)

Velocity

d)

Distance

8.

If you want acceleration to be the slope on a graph, what things need to be on the X and Y axis?

a)

Position

b)

Velocity

c)

Displacment

d)

Time

9.

What is 9.81m/s2?

a)

acceleration due to gravity

b)

constant g

c)

the velocity of a projectile

d)

constant G

10.

Which of the following will result in an average velocity of zero?

a)

An object does not move

b)

An object moves but comes back to where it started

c)

An object moves backward

d)

An object does not accelerate as it moves

11.

Which of the following would cause a speed that is positive?

a)

An object moving forwards

b)

An object moving backwards

c)

An object that is sitting still

d)

An object that is a projectile

e)

An object that is accelerating

12.

Constant acceleration on a position/time graph produces what shape?

a)

A flat, straight line

b)

An angled, straight line

c)

A curved line

d)

You cannot graph acceleration on a P/T graph

13.

Constant acceleration produces what shape on a velocity/time graph?

a)

A flat, straight line

b)

A flat, angled line

c)

A curved line

d)

You cannot graph acceleration on a V/T graph

14.

At the highest point on the path of a projectile, which of the following will be zero?

a)

Velocity

b)

Displacement

c)

Acceleration

d)

Time

15.

Two objects are moving in the same direction at different speeds. Object A is 2.2 m ahead of object B and is moving with a speed of 2.15 m/s. object B is moving with a velocity of 3.6 m/s.

Which of these is the next step in solving this problem?

a)

Write two position/time equations and set them equal to each other at vf

b)

Write two position/time equations and set them equal to each other at xf

c)

Write two velocity/time equations and set them equal to each other at vf

d)

Write two velocity/time equations and set them equal to each other at xf

16.

A boat is moving with a constant speed of 11.30 m/s. It speeds up with a constant acceleration of 2.40 m/s2 . use the velocity-time equation to calculate the velocity of the boat after accelerating for 5.00 s.

a)

23.3 m/s

b)

23.3 m/s2

c)

58.9 m/s

d)

58.9 m/s2

17.

A ramp is made from ground level to a step that is 0.64 m tall. It covers a horizontal distance of 1.98 m. Select the correct magnitude and correct angle below.

a)

2.08 meters

b)

4.33 meters

c)

32°

d)

18°

e)

72°

18.

A projectile is launched from a 6.0 m high platform at an angle of 48° with an initial velocity of 12.5 m/s. It will travel through the air in two dimensions (both horizontally and vertically) before hitting the ground.
Select the equations of a projectile below that has the numbers in the correct position.

a)

 xf=0+12.5(cos48)t x_f=0+12.5\left(\cos48\right)t\   

b)

 xf=6+12.5(cos48)tx_f=6+12.5\left(\cos48\right)t  

c)

 yf=6+12.5(sin48)t 12(9.81)t2y_f=6+12.5\left(\sin48\right)t\ -\frac{1}{2}\left(9.81\right)t^2  

d)

 yf=0+12.5(sin48)t12(9.81)t2y_f=0+12.5\left(\sin48\right)t-\frac{1}{2}\left(9.81\right)t^2  

e)

 yf=12.5 +0(sin48)t12(9.81)t2y_f=12.5\ +0\left(\sin48\right)t-\frac{1}{2}\left(9.81\right)t^2