WorksheetsStoichiometry Warm Up
Total questions: 10
Worksheet time: 13mins
Name
Class
Date
1.
In the equation 2 Al2O3 --> 4 Al + 3 O2, what is the mole ratio of aluminum to oxygen?
a)
10:6
b)
3:4
c)
4:3
d)
2:3
2.
Given the reaction: 4Al + 3O2 --> 2Al2O3
How many moles of Aluminum oxide do you have if you have 2 moles of Al?
How many moles of Aluminum oxide do you have if you have 2 moles of Al?
a)
3 mole
b)
2 mole
c)
1 mole
d)
0.5 mole
3.
N2 + 3H2 → 2NH3
What is the mole ratio between Nitrogen and Ammonium in the above reaction?
What is the mole ratio between Nitrogen and Ammonium in the above reaction?
a)
1 moles NH3 / 2 moles N2
b)
2 moles NH3 / 1 moles N2
c)
2 moles N2 / 3 moles NH3
d)
1 moles N2 / 3 moles NH3
4.
N2 + 3H2 --> 2NH3
What is the total number of moles of NH3 produced when 10 moles of H2 reacts completely with N2?
What is the total number of moles of NH3 produced when 10 moles of H2 reacts completely with N2?
a)
6.7
b)
2.0
c)
3.0
d)
15.0
5.
N2 + 3H2 --> 2NH3
How many moles of N2 is needed to react with 6 moles of H2?
How many moles of N2 is needed to react with 6 moles of H2?
a)
6.7
b)
2.0
c)
3.0
d)
15.0
6.
2 NaClO3 (s) --> 2NaCl (s) +3 O2 (g)
12.00 moles of NaClO3 will produce how many grams of O2?
12.00 moles of NaClO3 will produce how many grams of O2?
a)
256 g of O2
b)
576 g of O2
c)
288 g O2
7.
B2H6 + 3O2 -->2 HBO2 + 2 H2O
What mass of O2 will be needed to burn 36.1 g of B2H6?
What mass of O2 will be needed to burn 36.1 g of B2H6?
a)
13.8 g O2
b)
3.86 mol of O2
c)
124 g O2
8.
4 Al + 3 O2 –> 2 Al2O3 How much aluminum would be needed to completely react with 45 grams of O2?
a)
1.05 moles
b)
3.75 moles
c)
1.875 grams
d)
1.875 moles
9.
When 12 moles of O2 reacts with 1.1 mole of C10H8 what is the limiting reactant? C10H8 + 12 O2 --> 10 CO2 + 4 H2O
a)
Oxygen
b)
C10H8
c)
Water
d)
Carbon Dioxide
10.
In a lab, a scientist calculate he should produce 12.3 grams of product in his experiment. When he is finished collecting his product it weighs 10.1 grams. What is his percent yield?
a)
82%
b)
0.82%
c)
10.1 %
d)
100%
100 %
