WorksheetsFriction Lab Follow Up
Total questions: 8
Worksheet time: 4mins
A classroom desk supported by long legs is stationary in the room. A teacher comes around and pushes upon the desk in an effort to start it into a state of motion. The desk does not budge. The desk remains at rest because ______.
there is a force of static friction opposing its motion
there is a force of kinetic or sliding friction opposing its motion
there is a force of rolling friction opposing its motion
there are small dust mites at the desk's feet that push back on the desk to keep it at rest
A classroom desk supported by long legs is stationary in the room. A teacher comes around and pushes upon the desk in an effort to start it into a state of motion. The desk is finally accelerated from rest and then moves at a constant speed of 0.5 m/s. The desk maintains this constant speed
because
there is a force of static friction balancing the teacher's forward push
there is a force of kinetic or sliding friction balancing the teacher's forward push
there is a force of rolling friction balancing the teacher's forward push
the teacher must have stopped pushing
The symbol μ stands for the
coefficient of friction
force of friction
normal force
The units on μ are
Newton
kg
m/s/s
... nonsense! There are no units on μ.
Use the friction equation and Fnet = m•a to fill in the blanks in the following situations.
Force of friction = 10 N, 0.333=μ
Force of friction = 6.1 N, 0.51=μ
Force of friction = 6 N, 19.6 =a (right
Force of friction = 9.9 N, 0.82=μ
Use the friction equation and Fnet = m•a to fill in the blanks in the following situations.
Force of friction = 10 N, 0.333=μ
Force of friction = 6.1 N, 0.51=μ
Force of friction = 6 N, 19.6 =a (right
Force of friction = 9.9 N, 0.82=μ
Use the friction equation and Fnet = m•a to fill in the blanks in the following situations.
Force of friction = 10 N, 0.333=μ
Force of friction = 6.1 N, 0.51=μ
Force of friction = 6 N, 19.6 =a (right
Force of friction = 9.9 N, 0.82=μ
Use the friction equation and Fnet = m•a to fill in the blanks in the following situations.
Force of friction = 10 N, 0.333=μ
Force of friction = 6.1 N, 0.51=μ
Force of friction = 6 N, 19.6 =a (right
Force of friction = 9.9 N, 0.82=μ
