A 2.00-kg solid, uniform ball of radius 0.100 m is released from rest at point A as shown in the figure, its center of gravity a distance of 1.50 m above the ground. The ball rolls without slipping to the bottom of an incline and back up to point B where it is launched vertically into the air. The ball rises to its maximum height  $h_{\max}$   at point C. At point B, find the ball’s rotational speed. (The ball's moment of inertia is defined by  $I=\frac{2}{5}MR^2$  .)

A 2.00-kg solid, uniform ball of radius 0.100 m is released from rest at point A as shown in the figure, its center of gravity a distance of 1.50 m above the ground. The ball rolls without slipping to the bottom of an incline and back up to point B where it is launched vertically into the air. The ball rises to its maximum height  $h_{\max}$   at point C. At point C, find the ball’s rotational speed. (The ball's moment of inertia is defined by  $I=\frac{2}{5}MR^2$  .)

A 2.00-kg solid, uniform ball of radius 0.100 m is released from rest at point A as shown in the figure, its center of gravity a distance of 1.50 m above the ground. The ball rolls without slipping to the bottom of an incline and back up to point B where it is launched vertically into the air. The ball rises to its maximum height  $h_{\max}$   at point C. Find the ball's maximum height  $h_{\max}$  of its center of gravity. (The ball's moment of inertia is defined by  $I=\frac{2}{5}MR^2$  .)

A disk of mass m is spinning freely at 6.00 rad/s when a second identical disk, initially not spinning, is dropped onto it so that their axes coincide. In a short time the two disks are corotating. What is the angular speed of the new system?

A disk of mass m is spinning freely at 6.00 rad/s when a second identical disk, initially not spinning, is dropped onto it so that their axes coincide. In a short time the two disks are corotating. If a third such disk is dropped on the first two, find the final angular speed of the system.

A 0.00500-kg bullet traveling horizontally with a speed of

1.00 x 10³ m/s enters an 18.0-kg door, embedding itself 10.0 cm from the side opposite the hinges as shown. The 1.00-m-wide door is free to swing on its hinges. Before it hits the door, what is the angular momentum of the bullet?

A 0.00500-kg bullet traveling horizontally with a speed of
1.00 x 103 m/s enters an 18.0-kg door, embedding itself 10.0 cm from the side opposite the hinges as shown. The 1.00-m-wide door is free to swing on its hinges. At what angular speed does the door swing open immediately
after the collision? (The moment of inertia of the door is defined by  $I=\frac{1}{3}ML^2$  , where L is the length of the door.)

A 0.00500-kg bullet traveling horizontally with a speed of
1.00 x 103 m/s enters an 18.0-kg door, embedding itself 10.0 cm from the side opposite the hinges as shown. The 1.00-m-wide door is free to swing on its hinges. What is the kinetic energy of the bullet-door system after impact? (The moment of inertia of the door is defined by  $I=\frac{1}{3}ML^2$  , where L is the length of the door.)