WorksheetsElectricity (Review)
Total questions: 10
Worksheet time: 3hrs 30mins
Two charged particles Q1 = +10 μC and Q2 = +20 μC are separated by a distance r = 12 cm. What is the magnitude of the electrostatic force.
250 N
125 N
175 N
75 N
Three charged particles are arranged in a line as shown in figure below. Charge A = -5 μC, charge B = +10 μC and charge C = -12 μC. Calculate the net electrostatic force on particle B due to the charge C
275N
125 N
675 N
450 N
Q1 = 10 μC, +Q2 = 50 μC and Q3 are separated as shown in the figure below. What is the electrostatic charge on particle 3 if the net electrostatic force on particle 2 is zero.
90 x 10-6 C
45 x 10-6 C
90 x 10-9 C
45 x 10-9 C
A spherical conductor with 10 cm radius has a charge of 500 μC. Point A, B, and C are located in a straight line with a distance of 12 cm, 10 cm, dan 8 cm from the spherical center. Calculate the electric field at point A!
1,2 x 108 N/C
2,5 x 108 N/C
4,7 x 108 N/C
3,1 x 108 N/C
Three capacitors of capacitances 3μF, 9 μF and
18 μF are first connected in series and then in parallel. The ratio of the net capacitances in series to that in parallel is _____.
1:1
1:3
1:15
3:1
15:1
Four capacitors are connected in a circuit as shown below. If the voltage across the battery is 30V, then:
a) what is the total charge flowing through the circuit?
b) what is the charge flowing through the first capacitor on the left? (Think about the rules used in series and parallel circuits for charge)
a) 200 Micro Coulombs
b) 200 Micro Coulombs
a) 66.7 Micro Coulombs
b) 66.7 Micro Coulombs
a) 200 Micro Coulombs
b) 66.7 Micro Coulombs
a) 66.7 Micro Coulombs
b) 200 Micro Coulombs
Which of the following equations is/are a consequence of Kirchhoff’s rules, when applied to the figure below.
I only
II only
III only
I and II only
II and III only
Which of the following equations represent the current I in the circuit?
Consider the circuit shown in the figure below.
a) Apply Kirchhoff’s law to 𝑙𝑜𝑜𝑝 1 to find the current 𝑖1.
b) Apply Kirchhoff’s law to 𝑙𝑜𝑜𝑝 2 to find the current 𝑖2.
c) Find the current i3.
a) i1 = -1/2A
b) i2 = -1/3A
c) i3 = -5/6 A
a) i1 = -3/2A
b) i2 = -1/3A
c) i3 = -5/6 A
a) i1 = -1/2A
b) i2 = -1/3A
c) i3 = -1/6 A
a) i1 = -1/3A
b) i2 = -1/2A
c) i3 = -5/6 A
