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Which statement is true?
ΔGIA ∼ ΔTNA \Delta GIA\ \sim\ \Delta TNA\ ΔGIA ∼ ΔTNA by AA similarity
ΔGIA ∼ ΔTNA \Delta GIA\ \sim\ \Delta TNA\ ΔGIA ∼ ΔTNA by SSS similarity
ΔGIA ∼ ΔTNA\Delta GIA\ \sim\ \Delta TNAΔGIA ∼ ΔTNA by SAS similarity
ΔGIA\Delta GIAΔGIA can't be proven similar to ΔTNA\Delta TNAΔTNA
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