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WorksheetsDifferentiation and it's Application: ( Prepared by :NMK)
Total questions: 16
Worksheet time: 2hrs 36mins
dyd(2x2+5x+7)
5x+2
2x3+5
4x+5
5+4x
find dxdy for: y=(x+1)2
2x+2
2x+1
1+2x
2x+4
Given that y=5x+x21calulate the gradient of the curve at x=3
23145
13327
2755
27133
Given that PV=3600, find the value of dVdP when P=40
−49
−94
49
differentiate with respect to x: dxd(2x3+7)6
6x2(2x3+7)5
36x2(2x2+7)5
36x(2x3+7)5
36x2(2x3+7)5
(2,3)
(2,2)
(2,1)
(3,2)
Differentiate with respect to x: (x+7)10(x2+2)7
2(x+7)9(x2+2)6(12x2+49x+10)
2(x+7)8(x2+2)5(12x2+49x+10)
2(x+7)10(x2+2)6(24x2+49x+10)
6(x+7)9(x+2)6(12x2+49x+10)
Differentiate with respect to x: dxd(3x−42x+5)
−(3x−4)323
−(3x−4)232
(3x−4)223
−(3x−4)223
If v=t3+2t2+3t+1, calculate the value of dt2d2v when t=32
dt2d2v=100
dt2d2v=−20
dt2d2v=−10
dt2d2v=10
4%
5%
-4%
6%
The volume of the sphere is given by v=34πr3 ,where r is the radius. If there is 1.5% change in it's radius find the corresponding percentage change in it's volume.
4%
5%
4.5%
5.5%
Find the equation of the normal to the curve y=x3−2x2+3 at the point x=2
4y+x=14
4y+3x=14
y+x=14
4y+x=41
Given that y=x2−6x+15 , find the gradient of the normal (m) to the curve at (4,7)
m=-2
m= −21
m=21
m=−31
2 97
2 53
3 43
2 43
A spherical ball is being inflated at a rate of 20 scm3 . Find the rate of increase of its radius when it's surface area is 100π cm2
6π1 cm/s
4π1 cm/s
5π1 cm/s
5π2 cm/s
find the coordinates of the stationary points of y=x3−3x2+7 and determine the nature of the stationary points.
(0,7) max and (2,3)min
(0,2) max and (2,3)min
(2,3) max and (0,7)min
(0,7) min and (2,3)max
