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WorksheetsGraphing Quadratic Functions
Total questions: 25
Worksheet time: 2hrs 7mins
Which of the following is correct for the vertex of the parabola
f(x) = 2x2 + 8x - 12 ?
There is a local minimum at -2, -20
There is a local maximum at -2, -20
There is a local minimum at 2, 12
There is a local maximum at 2, 12
None of the above
The above shows part of the graph of the function f(x) = x2 − 2x − 8
What is the equation of its axis of symmetry?
y = -9
y = 1
x = 2
x = 1
The above shows part of the graph of the function f(x) = x2 + 2x − 15
What is the equation of its axis of symmetry?
y = -16
x = -1
x = -2
y = -1
None of the above
Which is the vertex of y = x2+ 16x + 71 ?
V(-8, 7)
V(-8, 3)
V(8, 10)
V(16, -2)
Find the y-intercept of f(x) = 2x2 - 2x + 1
(1,0)
(-2,0)
(0,1)
(0, -1)
Y = -3x2 +7x - 2
The parabola shown above has its minimum point at (0.5, -16). What is its equation?
f(x) = -4x2 - 4x -15
f(x) = 4x2 - 4x -15
f(x) = -4x2 + 4x -15
f(x) = -4x2 + 4x -15
A parabola has its maximum point at (-1, 49) The y-intercept is (0, 40)
What is its equation?
f(x) = -9x2 + 18x +40
f(x) = 9x2 + 18x - 40
f(x) = 9x2 - 18x +40
f(x) = -9x2 -18x + 40
y=-(x-4)2-3,
does this parabola have a maximum or minimum value?
Find the y-intercept of the function
y = -3(x + 2)2 - 5
(0, -5)
(-2, -5)
(0, -17)
(2, -5)
y = -2x2 +8x-6
y = -4x2
have a maximum or minimum value?
