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Worksheets

Constructing and solving equations

Total questions: 28

Worksheet time: 14mins

Name
Class
Date
1.

Solve the equation: x+3=10x+3=10   

a)

13

b)

7

c)

103

d)

310

2.

Solve the equation: 2x+5=132x+5=13   

a)

36

b)

16

c)

9

d)

4

3.

12 subtracted from a number gives us 8. Find the number

a)

20

b)

4

c)

12

d)

8

4.

Find a number that is 3 times the sum of 5 and 7

a)

36

b)

22

c)

4

d)

8

5.

"A number is 3 times the sum of 5 and 7"

What operation we should use instead of the word "sum"?

a)

multiplication

b)

addition

c)

division

d)

subtraction

6.

"A number is 3 times the sum of 5 and 7"

What operation we should use instead of the word "times"?

a)

multiplication

b)

addition

c)

division

d)

subtraction

7.

"A number is 3 times the sum of 5 and 7"

What symbol we should use instead of the word "is"?

a)

-

b)

++

c)

×\times

d)

==

8.

The perimeter of this triangle is 19cm. Work out the value of t. (All lengths on the picture are in cm)

a)

4134\frac{1}{3}

b)

143\frac{14}{3}

c)

132\frac{13}{2}

d)

3133\frac{1}{3}

9.

Work out the value of x.

a)

75

b)

55

c)

50

d)

25

10.

Work out all the angles of this triangle.

a)

75; 50; 25

b)

75; 55; 50

c)

75; 60; 50

d)

55; 50; 25

11.

The perimeter of the parallelogram is 24 cm. Work out the value of x.

a)

7

b)

5

c)

3

d)

1

12.

The perimeter of the parallelogram is 24 cm. Work out the value of the smallest side.

a)

7

b)

5

c)

3

d)

1

13.

Clifford thinks of a number. He multiplies it by 3 then adds 8. The answer is 23. What number did he think of?

a)

6

b)

5

c)

313\frac{31}{3}

d)

45

14.

Gavriel thinks of a number. He divides it by 4 then subtracts 8. The answer is 5. What number did he think of?

a)

52

b)

3

c)

 134\frac{13}{4} 

d)

12

15.

Jyouju thinks of a number. He multiplies it by 3 then adds 7. The answer is the same as 4 times the number. What number did he think of?

a)

6

b)

7

c)

8

d)

9

16.

Work out the value of x and y in this rectangle.

a)

x = 8; y = 7

b)

x = 7; y = 8

c)

x = 7; y = 4

d)

x = 4; y = 7

17.

Work out the value of x in this isosceles triangle.

a)

2

b)

4

c)

12

d)

48

18.

Work out the value of y in this isosceles trapezoid

a)

4

b)

7

c)

14

d)

20

19.

Work out the value of x in this isosceles triangle.

a)

2

b)

4

c)

12

d)

48

20.

Work out the value of y in this parallelogram.

a)

4

b)

7

c)

14

d)

20

21.

Work out the value of x in this isosceles triangle.

a)

2

b)

4

c)

12

d)

48

22.

Work out the value of x and y in this rectangle.

a)

x = 8; y = 7

b)

x = 7; y = 8

c)

x = 7; y = 4

d)

x = 4; y = 7

23.

Fathir thinks of a number. He multiplies it by 5 then subtracts 4. The answer is the same as 2 times the number and plus 20. 

Construct the right equation.

a)

 5x4=2x+205x-4=2x+20  

b)

 5(x4) = 2 (x+20)5\left(x-4\right)\ =\ 2\ \left(x+20\right)  

c)

 5(x4) = 2 (x+20)5\left(x-4\right)\ =\ 2\ \left(x+20\right)  

d)

 5x4 = 2x205x-4\ =\ 2x-20  

24.

Fathir thinks of a number. He multiplies it by 5 then subtracts 4. The answer is the same as 2 times the number and plus 20. What number did he think of?

a)

6

b)

7

c)

8

d)

9

25.

Noval thinks of a number. He adds 5 then multiplies the result by 2. The answer is the same as 6 times the number take away 14.
Construct the right equation.

a)

 (x+5)×2 = 6x + 14\left(x+5\right)\times2\ =\ 6x\ +\ 14  

b)

 2(x+5) = 6x 142\left(x+5\right)\ =\ 6x\ -14  

c)

 x+5×2 = 6x  14x+5\times2\ =\ 6x\ -\ 14  

d)

 2x+5= 6x + 142x+5=\ 6x\ +\ 14  

26.

Noval thinks of a number. He adds 5 then multiplies the result by 2. The answer is the same as 6 times the number take away 14. What number did he think of?

a)

6

b)

7

c)

8

d)

9

27.

Bayu thinks of a number. He subtracts 2 then multiplies the result by 3. The answer is the same as subtracting 6 from the number then multiplying by 7. 

Construct the right equation.

a)

 3x2 = 7(x6)3x-2\ =\ 7\left(x-6\right)  

b)

 (x2)3 = x6×7\left(x-2\right)3\ =\ x-6\times7  

c)

 (x2) 3= (x6)÷7\left(x-2\right)\ 3=\ \left(x-6\right)\div7  

d)

 3(x2) = (x6)73\left(x-2\right)\ =\ \left(x-6\right)7  

28.

Bayu thinks of a number. He subtracts 2 then multiplies the result by 3. The answer is the same as subtracting 6 from the number then multiplying by 7. What number did he think of?

a)

6

b)

7

c)

8

d)

9