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3+4⋅5÷10= ?3+4\cdot5\div10=\ ?3+4⋅5÷10= ?
2
3
4
5
(8+5⋅2)÷(9⋅2−12)= ?\left(8+5\cdot2\right)\div\left(9\cdot2-12\right)=\ ?(8+5⋅2)÷(9⋅2−12)= ?
1 − (4−5⋅2)÷(2⋅4−2) = ?1\ -\ \left(4-5\cdot2\right)\div\left(2\cdot4-2\right)\ =\ ?1 − (4−5⋅2)÷(2⋅4−2) = ?
1
0
(4−3−2−1)÷(1−2−3−4) = ?\left(4-3-2-1\right)\div\left(1-2-3-4\right)\ =\ ?(4−3−2−1)÷(1−2−3−4) = ?
−14-\frac{1}{4}−41
−12-\frac{1}{2}−21
14\frac{1}{4}41
12\frac{1}{2}21
34⋅23÷12+12= ?\frac{3}{4}\cdot\frac{2}{3}\div\frac{1}{2}+\frac{1}{2}=\ ?43⋅32÷21+21= ?
23\frac{2}{3}32
34\frac{3}{4}43
32\frac{3}{2}23
(23⋅35÷25)−(34÷12÷32)+(18+38−12)= ?\left(\frac{2}{3}\cdot\frac{3}{5}\div\frac{2}{5}\right)-\left(\frac{3}{4}\div\frac{1}{2}\div\frac{3}{2}\right)+\left(\frac{1}{8}+\frac{3}{8}-\frac{1}{2}\right)=\ ?(32⋅53÷52)−(43÷21÷23)+(81+83−21)= ?
(((12)1)−2)3÷((12)6−(18)2+(164))0\left(\left(\left(\frac{1}{2}\right)^1\right)^{-2}\right)^3\div\left(\left(\frac{1}{2}\right)^6-\left(\frac{1}{8}\right)^2+\left(\sqrt{\frac{1}{64}}\right)\right)^0⎝⎛((21)1)−2⎠⎞3÷((21)6−(81)2+(641))0
64
32
8
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