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Pengaturan lainnya
2АМ<Р
2АМ>Р
2АМ=Р
3АМ<Р
x∈[10;+∞)x\in\left[10;+\infty\right)x∈[10;+∞)
x∈[7;+∞)x\in\left[7;+\infty\right)x∈[7;+∞)
x∈(−∞;10]x\in\left(-\infty;10\right]x∈(−∞;10]
x∈[−5;+∞)x\in\left[-5;+\infty\right)x∈[−5;+∞)
Ако а > 7 и b < 3, то със сигурност:
a−b>4a-b>4a−b>4
a−b<4a-b<4a−b<4
a+b<10a+b<10a+b<10
a−b>10a-b>10a−b>10
Ако a<ba<ba<b , то не е вярно неравенството:
−2-2−2
−3-3−3
000
−8-8−8
Най-голямото цяло число, което е решение на неравенството (x2 +1)(5−x)≥0\left(x^2\ +1\right)\left(5-x\right)\ge0(x2 +1)(5−x)≥0
666
444
555
Числото 3 е решение на неравенството:
2(x−3)<3(x−1)2\left(x-3\right)<3\left(x-1\right)2(x−3)<3(x−1)
3x−1>5x−73x-1>5x-73x−1>5x−7
5(x−1)>7(x+1)5\left(x-1\right)>7\left(x+1\right)5(x−1)>7(x+1)
5x−1>2x+85x-1>2x+85x−1>2x+8
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