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Skalarni produkt vektora

Total questions: 6

Worksheet time: 30mins

Name
Class
Date
1.

Odredi skalarni produkt vektora  a→=12i→+2j→\overrightarrow{a}=\frac{1}{2}\overrightarrow{i}+2\overrightarrow{j}  i  b→=−2i→+j→\overrightarrow{b}=-2\overrightarrow{i}+\overrightarrow{j}  koristeći formulu  a→⋅b→=xa⋅xb+ya⋅yb\overrightarrow{a}\cdot\overrightarrow{b}=x_a\cdot x_b+y_a\cdot y_b  

a)

1

b)

3

c)

-2

d)

-1

2.

Ako je ∣a→∣=2\left|\overrightarrow{a}\right|=2 , ∣b→∣=1\left|\overrightarrow{b}\right|=1  i  ∠(a→,b→)=60°\angle\left(\overrightarrow{a},\overrightarrow{b}\right)=60° , odredi a→⋅b→\overrightarrow{a}\cdot\overrightarrow{b} . Sjeti se: a→⋅b→=∣a→∣⋅∣b→∣⋅cos⁡∠(a→,b→)\overrightarrow{a}\cdot\overrightarrow{b}=\left|\overrightarrow{a}\right|\cdot\left|\overrightarrow{b}\right|\cdot\cos\angle\left(\overrightarrow{a},\overrightarrow{b}\right) 

a)

120°

b)

2

c)

1

d)

 2\sqrt{2}  

3.

Ako je ∣a→∣=2\left|\overrightarrow{a}\right|=2 , ∣b→∣=1\left|\overrightarrow{b}\right|=1  i  a→⋅b→=1\overrightarrow{a}\cdot\overrightarrow{b}=1 , odredi  ∠(a→,b→)\angle\left(\overrightarrow{a},\overrightarrow{b}\right) . Sjeti se: a→⋅b→=∣a→∣⋅∣b→∣⋅cos⁡∠(a→,b→)\overrightarrow{a}\cdot\overrightarrow{b}=\left|\overrightarrow{a}\right|\cdot\left|\overrightarrow{b}\right|\cdot\cos\angle\left(\overrightarrow{a},\overrightarrow{b}\right) 

a)

 12\frac{1}{2}  

b)

 60°60°  

c)

 90°90°  

d)

 30°30°  

4.

Odredite skalarni produkt vektora  a→=−7i→+4j → i  b→=12i→−3 j→\overrightarrow{a}=-7\overrightarrow{i}+4\overrightarrow{j\ }\ i\ \ \overrightarrow{b}=12\overrightarrow{i}-3\ \overrightarrow{j}  

a)

84

b)

-84

c)

96

d)

-96

5.

Odredite kut između vektora  a→=−7i→+4j →  i   b→=12i →−3j→\overrightarrow{a}=-7\overrightarrow{i}+4\overrightarrow{j\ }\ \ i\ \ \ \overrightarrow{b}=12\overrightarrow{i\ }-3\overrightarrow{j}  

a)

 164°17‘ 29‘‘164\degree17`\ 29``  

b)

 166°12‘166\degree12`  

c)

 45°34´15‘‘45\degree34´15``  

d)

 123°34‘23‘‘123\degree34`23``  

6.

Za koji y su vektori  a→=−3i→+j →  i  b→=2i→−yj→\overrightarrow{a}=-3\overrightarrow{i}+\overrightarrow{j\ }\ \ i\ \overrightarrow{\ b}=2\overrightarrow{i}-y\overrightarrow{j}  okomiti?

a)

 −6-6  

b)

 33  

c)

 −3-3  

d)

 66