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PHYSICS CLASS WORK

Total questions: 15

Worksheet time: 22mins

Name
Class
Date
1.

To calculate magnification of an electron micrograph we use......

a)

magnification = image size x actual size

b)

magnification = image size ÷ actual size

c)

magnification = actual size ÷ field of view

d)

magnification = eyepiece lens x objective lens

2.

To calculate the image size of an electron micrograph if we use.....

a)

Image size = Actual size x Magnification

b)

Image size = Magnification ÷ Actual size

c)

Image size = Actual size ÷ magnification

d)

Image size = Magnification x Actual size

3.

Josie measured the scale bar image to be 80 mm. What is the Magnification of this electron micrograph?

I = AM

a)

160X

b)

0.00625 X

c)

0.16X

d)

25,000X

4.

If the scale bar measures 60 mm and the actual size it represents is 30 μm , what is the magnification?

a)

20X

b)

5,000X

c)

150X

d)

2,000X

5.

If a scale bar measures 32 mm and it states it's length is 100 μm, what is the magnification?

a)

0.32 x

b)

3,200 x

c)

320 x

d)

32,000 x

6.

If a bacteria image measures 450 mm and the magnification is 15,000x, what is the actual size of the bacteria?

a)

30 µm

b)

0.3 µm

c)

300 µm

d)

3,000 µm

7.

Serena measured the image of one of the bacterial cells to be 32 mm. If the magnification of the image is 8,000X, what is the actual size of the bacterial cell?

a)

4 μm

b)

0.004 μm

c)

256,000 μm

d)

0.25 μm

8.

What steps should Burt follow to calculate the actual size of each bacterial cell?

a)

Step 1: Measure the image of the bacterial cell

Step 2: Divide the image size by the scale bar size

b)

Step 1: Calculate the magnification by measuring the scale bar image x actual size

Step 2: Measure image of bacterial cell ÷ magnification

c)

Step 1: Calculate the magnification by measuring the scale bar image ÷ actual size

Step 2: Measure image of bacterial cell ÷ magnification

d)

He can't, it is impossible to calculate

9.

An object is placed 20 cm at the left side of a biconcave lens with focal length of 12 cm. Find the position of the image formed.

a)

7.5 cm

b)

-30 cm

c)

30 cm

d)

-7.5 cm

10.

State the characteristic of image foremd

a)

real, upright and diminished

b)

real, inverted and diminished

c)

virtual, upright and magnified

d)

virtual, upright and diminished

11.

Calculate the focal length when given u=15cm and a virtual image at 25 cm is formed. State the type of lens used.

a)

37.5 cm (biconcave lens)

b)

-37.5 cm (biconcave lens)

c)

37.5 cm (biconvex lens)

d)

9.4 cm (biconvex lens)

12.

What is the formula for magnification?

a)

-v / u

b)

-hi / ho

c)

hi / ho

d)

v/u

13.

Magnification produced by concave lens is always ______

a)

> 1

b)

< 1

c)

1\ge1

d)

=1

14.

To obtain a magnification of 2.5, how far should an object be placed from the pole of a thin converging lens of focal length 10.20 m?

a)

0.13 m

b)

0.25 m

c)

0.28 m

d)

0.50 m

15.

An object is placed 5.6 x 10-4 m in front of a converging lens of focal length 1.0 x 10-2 m. The image formed is

a)

real, erect and magnified.

b)

virtual, erect and magnified.

c)

real, inverted and magnified.

d)

virtual, erect and diminished.