WorksheetsЖаңа тригонометрия Балмира
Total questions: 23
Worksheet time: 12mins
4sin33x−sin3x=2+sin3x
x=3π+2π
x=6π+32πn; x=(−1)k+1 31arcsin 32+3πn
x=6π+3π x= arcsin 31+2π
x=6π+32πn ; x=32arcsin31+3πn
2cos2x−5cosx=−3
2πn
4πn
πn
2π
cos23x=21
6π+6πk
12π+6πk
4π+6πn
8π+8πn
2cos2x+3=0
x=±125π+πk
x=125π
x=±12π+πk
x=±125π+2πk
6sin2x−cosx−5=0
x= arccos 31+πk
x=±34π+2πk
x=±32π+2πn ; x=arccos 31+2πk
x=±3π+πk; x=arccos 31+2πk
6cos2x+sinx−5=0
x=32π+πk
x=(−1)k 6π+2πk; arcsin 31+2ππk
x=6π+πk; 32π+πn
x=(−1)k 6π+πn ;(−1)k+1 arcsin 31+πn
(2sin 2x−2 cos 2x)2=5+sin (4x−2x)
2π+πk
23π+4πk
65π+4πk
6π+πk
sin3xcos3x=−21
−12π+3πn
12π+3π+πk
−6π+3πk
6π+3πk
−3ctg(x+5π)=1
x=125π+πk
x=157π+πk
x=73π+πk
x=152π+πk
sin(3π−2x)cos(3π−2x)≥4−3
[−6π+2π;6π+2π]
[−6π+2πn;4π+2πn]
[−3π+πn;3π+πn]
[−6π+3πn;4π+3πn]
cos2x≥0.25
[−4π+πn;4π+πn]
[−3π+πn;3π+πn]
[−3π+2πn;3π+2πn]
[−6π+πn;6π+πn]
−3ctg(x−5π)≤1
15π+πn;4π+πn
5π+πn
−5π+πn;157π+πn
−12π+πn;3π+πn
2cos2(x+4π)−3cos2x≤0
(−3π+πn)
[−12π+πn;4π+πn]
[−15π+πn;6π+πn]
[−8π+πn;8π+πn]
πn
[πn;4π+πn]
[3π+πn]
[πn;6π+πn]
(sin2x+3cos2x)2=5+cos(2x−6π)
125π+πn
127π+πn
πn
2πn
sin2xcos6x алғашқы функциясын табыңыз
41cos4x−81cos8x+4 ; 81cos4x−161cos8x+1
21cos8x−21sin6x+5 ;31sin8x+51cos4x+6
161cos4x+81sin2x; 81sin5x+81cos2x
∫6π3π(cos2(x+3π)−sin2(x+3π))dx
−42
23 немесе 3
−43 немесе −433
3
sin27x−cos27x=23
±845π+7πk
875π+7πk
±857π+7π
±745π+7πk
{2sinx+cosy=1; 2sinx+3cosy=2} жүйесінің шешімі
((−1)k3π+2π;2π+πn)
(4π+πn;6π+πn)
((−1)k 4π+πn; 2π+πn)
f(x)=x2−2x ;g(x)=sin7x f((6π))=?
54
45
−43
−21
{sin3x>21;tgx>3} жүйенің шешімі
(1825π+2πn; 23π+2πn)
(1823π+2πn;23π+2πn)
(1625π+πn;32π+2πn)
cos(2x−3π)≥22
18π+πn
24π+πn;247π+πn
−24π+πn;245π+πn
cos(3π−2x)−cos(6π+2x)=1
x=±4π+24ππn
x=±6π+285π+πn
x=±8π+247π+πn
