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Linkage mapping

Total questions: 20

Worksheet time: 52mins

Name
Class
Date
1.

Linkage is a phenomenon seen during.....

a)

Mitosis

b)

Meiosis

c)

DNA replication

d)

During a mutation

2.

Crossingover occurs between

a)

Homologous Non sisters

b)

Homologous Sisters

c)

Between both homologous sisters and non sisters

d)

Occurs between different crhomosomes

3.

What is the difference between Chromatin and Chromosomes? (1 mark)

4 lines
4.

How many genes can be mapped with the help of a double crossover?

a)

3

b)

2

c)

4

d)

either 2 or 3

5.

If Crossing over is a tool for generating variation in the population, then what is the purpose of the S phase in the cell cycle

a)

S phase is the phase in which mutations mostly occur in the DNA of the cell

b)

S phase is the phase during which DNA is getting condensed to form a chromosome

c)

S phase is the phase during which DNA is replicated in the cell

d)

S phase is the phase during which the proteins needed for mitosis are prepared

6.

The corssing over happens in which stage of Meiosis

a)

Prophase I: Zygotene

b)

Prophase II: Zygotene

c)

Prophase II: Pachytene

d)

Anaphase

e)

Prophase I: Pachytene

7.

The progeny of a test cross is not in a 1:1 ratio, this means

a)

Independent assortment failed to occur

b)

Segregation failed to occur

c)

There was some error in data analysis, the progeny of a test cross are always 1:1

d)

This is because of a lethal gene influence

8.

Why is a test cross always performed when we need to map the gene distance? (2 marks)

4 lines
9.

How many progeny will be have if we have 3 genes that are being mapped?

a)

9

b)

8

c)

4

d)

6

10.

During Meiosis at the tetrad stage the paternal chromosome and the maternal chromosome are accurately described as

a)

Homologue sister

b)

homologues

c)

Non Homologue sister

d)

Homologue non sister

e)

sister homologues

11.

If the distance between A/B is 0.12 mu and gene C is on the opposite side of A with respect to B at a distance of 0.23 mu, Which is the central gene in this map

a)

A

b)

B

c)

C

d)

Data insufficient

12.

If the distance between A/B is 0.12 mu and gene C is on the opposite side of A with respect to B at a distance of 0.23 mu, What is the order of the gene linkage map

a)

A - B - C

b)

C - A - B

c)

both A - B - C and C - B - A are possible

d)

The linkage map cannot be detemined as the ratio is not 1:1

e)

A - C - B

13.

If the distance between A/B is 0.12 mu and gene C is on the opposite side of A with respect to B at a distance of 0.23 mu, then distance A/C is (choose the most accurate option)

a)

equal to 0.35 mu

b)

greater than 0.35 mu

c)

lesser than 0.35 mu

d)

equal to or lesser than 0.35 mu

e)

equal to or greater than 0.35 mu

14.

A cross is made between vermilion (v), scute (sc), yellow body (y) fly and a wild type fly. The F1 is test crossed and the F2 progeny are as follows: + + + = 489, v sc y = 470, + sc y = 210, v + + = 218, + + y = 10, v sc + = 6, + sc + = 156, v + y = 141. What is the distance between v & sc and which is the central gene. (1 mk)

a)

v/sc = 0.42 mu and v is the central gene

b)

v/sc = 0.24 mu and y is the central gene

c)

v/sc = 0.42 mu and y is the central gene

d)

v/sc = 0.24 and v is the central gene

15.

A cross is made between vermilion (v), scute (sc), yellow body (y) fly and a wild type fly. The F1 is test crossed and the F2 progeny are as follows: + + + = 489, v sc y = 470, + sc y = 210, v + + = 218, + + y = 10, v sc + = 6, + sc + = 156, v + y = 141. What is the COC in this cross (1 mk)

a)

0.01875

b)

0.2856

c)

0.1875

d)

1.562

16.

A cross is made between vermilion (v), scute (sc), yellow body (y) fly and a wild type fly. The F1 is test crossed and the F2 progeny are as follows: + + + = 489, v sc y = 470, + sc y = 210, v + + = 218, + + y = 10, v sc + = 6, + sc + = 156, v + y = 141. What is the interference in this cross

a)

91.26%

b)

81.25%

c)

18.75%

d)

28.75%

17.

This is the reason why Mendel did not recognize linkage phenomenon in his experiments

a)

The characters he studied were present on different chromosomes

b)

He studied only pure characters

c)

He did not have a powerful microscope

d)

The characters he studied did show linkage but he missed it

18.

What Chromosomes are to Mitosis, Chromatin is to (a)  

19.
1 map unit is equal to:
a)
1 nm
b)
1% recombination
c)
1 chromosome
d)
1 mutation
20.
Causes genes to not segregate independently. Causes genes to be more likely to be inherited together. Represents an exception to Mendel's Law of Independent assortment.
a)
Gene linkage
b)
Epistasis
c)
Polygenic traits
d)
Codominance