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Dimensional Analysis (Showing the Steps!)

Total questions: 6

Worksheet time: 6mins

Name
Class
Date
1.

Which of the following shows the correct work to convert 25.0 inches to cm? (Relationship: 1 inch = 2.54 cm)

a)

 25.0 in  x  2.54 cm1 in=25.0\ in\ \ x\ \ \frac{2.54\ cm}{1\ in}=  

b)

 2.54 cm x 1 in25.0 cm=2.54\ cm\ x\ \frac{1\ in}{25.0\ cm}=  

c)

 1 in x 2.54 cm25 in=1\ in\ x\ \frac{2.54\ cm}{25\ in}=  

d)

 25 in x 1 in2.54 cm=25\ in\ x\ \frac{1\ in}{2.54\ cm}=  

2.

Which of the following choices shows the correct setup to find out how many yards are in 575 inches?

a)

 575 yd  x  3 ft1 yd x 12 in1 ft=575\ yd\ \ x\ \ \frac{3\ ft}{1\ yd}\ x\ \frac{12\ in}{1\ ft}= 

b)

 575 in  x  1 ft12 in x 1 yd3 ft=575\ in\ \ x\ \ \frac{1\ ft}{12\ in}\ x\ \frac{1\ yd}{3\ ft}= 

c)

 575 in  x  12 in1 ft x  3 ft1 yd = 575\ in\ \ x\ \ \frac{12\ in}{1\ ft}\ x\ \ \frac{3\ ft}{1\ yd}\ =\  

d)

 575 in  x 1 ft12 in x  3 ft1 yd=575\ in\ \ x\ \frac{1\ ft}{12\ in}\ x\ \ \frac{3\ ft}{1\ yd}= 

3.

This is the correct setup to find out how many seconds are in 31 days. Solve it using a calculator!

 31 days x 24 hr1 dayx 60 min1 hrx 60 s1 min = 31\ days\ x\ \frac{24\ hr}{1\ day}x\ \frac{60\ \min}{1\ hr}x\ \frac{60\ s}{1\ \min}\ =\   

a)

44640 seconds

b)

1,000,000 seconds

c)

2,678,400 seconds

d)

525,600 minutes

4.

If 1 mile = 1.61 km, what is the correct work to solve how many miles are in 9,999 meters?

a)

 9,999 m x 1.61 km1 m x 1 mi1000 m=9,999\ m\ x\ \frac{1.61\ km}{1\ m}\ x\ \frac{1\ mi}{1000\ m}=  

b)

 9,999 m x 1 km1000 mx 1 mi1.61 km=9,999\ m\ x\ \frac{1\ km}{1000\ m}x\ \frac{1\ mi}{1.61\ km}=  

c)

 1.61 km x 1 mi1000 kmx 9999 m1 mi=1.61\ km\ x\ \frac{1\ mi}{1000\ km}x\ \frac{9999\ m}{1\ mi}=  

d)

 9,999 m x 1.61 km1 mi = 9,999\ m\ x\ \frac{1.61\ km}{1\ mi}\ =\   

5.

What is the correct setup to convert 82 meters per second into meters per hour?

a)

 82 mps x 60 s1 minx 1min60 hr=82\ mps\ x\ \frac{60\ s}{1\ \min}x\ \frac{1\min}{60\ hr}=  

b)

 82 m1 s x 1 mi1,609 m x 60 s1 min x 60 min1 hr=\frac{82\ m}{1\ s}\ x\ \frac{1\ mi}{1,609\ m}\ x\ \frac{60\ s}{1\ \min}\ x\ \frac{60\ \min}{1\ hr}=  

c)

 82 m1 s x 60 s1 min x 60 min1 hr=\frac{82\ m}{1\ s}\ x\ \frac{60\ s}{1\ \min}\ x\ \frac{60\ \min}{1\ hr}=  

d)

 82 m1 s x 1 s60 min x 1 min60 hr=\frac{82\ m}{1\ s}\ x\ \frac{1\ s}{60\ \min}\ x\ \frac{1\ \min}{60\ hr}=  

6.

What is the correct setup to convert 15 miles per hour into meters per second? (Relationship: 1,609 m = 1 mile)

a)

 15 mi1 hr x 60 hr1 min x 60 min1 sec x 1609 m1 mi=\frac{15\ mi}{1\ hr}\ x\ \frac{60\ hr}{1\ \min}\ x\ \frac{60\ \min}{1\ \sec}\ x\ \frac{1609\ m}{1\ mi}=  

b)

 15 mph  x 1609 m1 mi x 60 min1 hr x 60 s1 min = 15\ mph\ \ x\ \frac{1609\ m}{1\ mi}\ x\ \frac{60\ \min}{1\ hr}\ x\ \frac{60\ s}{1\ \min}\ =\   

c)

 15 mi1 hr x 1 m1609 mi x 1 hr60 min x 60 min1 s=\frac{15\ mi}{1\ hr}\ x\ \frac{1\ m}{1609\ mi}\ x\ \frac{1\ hr}{60\ \min}\ x\ \frac{60\ \min}{1\ s}=  

d)

 15 mi1 hr x 1,609 m1 mi  x 1 hr60 min x 1 min60 s=\frac{15\ mi}{1\ hr}\ x\ \frac{1,609\ m}{1\ mi}\ \ x\ \frac{1\ hr}{60\ \min}\ x\ \frac{1\ \min}{60\ s}=