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Recursive Equations: Unit 1 Test Review

Total questions: 10

Worksheet time: 50mins

Name
Class
Date
1.
Given the recursive formula, find the first four terms:
an = an-1 + 5
a1 = -16
a)
-16, -21, -26, -31
b)
5, -11, -27, -43
c)
-16, -80, -500, -200
d)
-16, -11, -6, -1
2.
Write a recursive rule for the sequence 17, 1, -15, -31 . . .
a)
an = an-1 + 16
a1=17
b)
an = an-1 - 17
a1=17
c)
an = an-1 - 15
a1=17
d)
an = an-1 - 16
a1=17
3.
Given the first five terms, write the recursive formula.
15, 12, 9, 6, 3 ....
a)
u1 = 15
un = un-1 + 3
b)
u0 = 15
un = un-1 + 3
c)
u1 = 15
un = un-1 - 3 
d)
u0 = 15
un = un-1 - 3
4.

Given the recursive formula below, find the explicit formula.

a1= 6

an = an-1 + 5

a)

an = 6 + 5n

b)

an = 1 + 5n

c)

an = 11 + 5n

d)

an = -4 + 5n

5.

Given the recursive formula below, find the explicit formula.

a1 = 5

an = an-1 - 6

a)

an = 5 - 6n

b)

an = 11 - 6n

c)

an = -6 +5n

d)

an = -6 + 11n

6.

Which of the following recursive formulas represents the given sequence.


7, 14, 28, 56, 112, ...

a)

a1=7a_1=7 , an=a(n−1)+7a_n=a_{\left(n-1\right)}+7

b)

a1=7a_1=7 , an=a(n−1)⋅7a_n=a_{\left(n-1\right)}\cdot7

c)

a1=7a_1=7 , an=a(n−1)⋅2a_n=a_{\left(n-1\right)}\cdot2

d)

a1=7a_1=7 , an=a(n−1)+14a_n=a_{\left(n-1\right)}+14

7.

Determine the 3rd term of the sequence.
 a1=5a_1=5  

 an=2⋅an−1−1a_n=2\cdot a_{n-1}-1  

a)

14

b)

13

c)

17

d)

16

8.

Given the recursive formula, find the explicit form

an = an-1 - 5

a1 = 22

a)

an = 22 - 5(n-1)

b)

an = 22 +5 (n-1)

c)

an = -5 + 22n

d)

an = 22-5n

9.

Determine the first 3 terms of the following sequence. tn=3⋅tn−1t_n=3\cdot t_{n-1}  ,  t1=−3t_1=-3  

a)

-3, 9, 27

b)

-3, -9, -27

c)

-3, -6, -9

d)

-3, 6,9

10.

 f(n)=  24 (12)(n−1)f\left(n\right)=\ \ 24\ \left(\frac{1}{2}\right)^{\left(n-1\right)}  Given the explicit formula, find the recursive equation.

a)

 a1=24a_1=24  ,  an=12⋅an−1a_n=\frac{1}{2}\cdot a_{n-1}   

b)

 a1=24a_1=24 ,  an=2⋅an−1a_n=2\cdot a_{n-1}  

c)

 a1=12, an=12⋅an−1a_1=12,\ a_n=\frac{1}{2}\cdot a_{n-1}  

d)

 a1=48, an=12⋅an−1a_1=48,\ a_n=\frac{1}{2}\cdot a_{n-1}