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Unit 1 Review

Total questions: 13

Worksheet time: 1hrs 5mins

Name
Class
Date
1.

#1 Evaluate:

 x+4−y−x2x+4-y-x^2  use  x=3 and y=−2x=3\ and\ y=-2  

a)

-4

b)

0

c)

14

d)

18

2.

#3 Simplify: 4x(x−2)−5x(2x+4)4x\left(x-2\right)-5x\left(2x+4\right)  


a)

 −6x2−28x-6x^2-28x  

b)

 6x2+28x6x^2+28x  

c)

 14x2+28x14x^2+28x  

d)

 14x2−12x14x^2-12x  

3.

#5 Simplify: 18(29x−19y−56x−3y)18\left(\frac{2}{9}x-\frac{1}{9}y-\frac{5}{6}x-3y_{ }\right)  


a)

11x-56y

b)

-15x-54y

c)

-11x-56y

d)

-19x-56y

4.

#7 Solve: p+196=−p+pp+\frac{19}{6}=-p+p  


a)

 p=−196p=-\frac{19}{6}  

b)

 p=196p=\frac{19}{6}  

c)

 p=619p=\frac{6}{19}  

d)

 p=−619p=-\frac{6}{19}  

5.

#9 Solve: x+14=254−2xx+\frac{1}{4}=\frac{25}{4}-2x  


a)

 x=−1x=-1  

b)

 x=0x=0  

c)

 x=1x=1  

d)

 x=2x=2  

6.

#11 Solve the inequality: −5−r>7-5-r>7  


a)

 r>12r>12  

b)

 r<12r<12  

c)

 r<−12r<-12  

d)

 r>−12r>-12  

7.

#13 Solve the inequality: 88≤8(v+3)88\le8\left(v+3\right)  


a)

 v≥8v\ge8  

b)

 v≤8v\le8  

c)

 v≤14v\le14  

d)

 v≥14v\ge14  

8.

#15 Solve the compound inequality: −43≤2−5p<52-43\le2-5p<52  


a)

 −10<p≤9-10<p\le9  

b)

 −10<p≤−9-10<p\le-9  

c)

 18≤p<2018\le p<20  

d)

 −18≤p<20-18\le p<20  

9.

#17 Solve the absolute value equation:  ∣−7x∣=49\left|-7x\right|=49  

a)

 x=−7x=-7  

b)

no solution

c)

 x=56, x=−42x=56,\ x=-42  

d)

 x=7, x=−7x=7,\ x=-7  

10.

#19 Solve the absolute value equation:  4∣−4p−1∣+6=104\left|-4p-1\right|+6=10  



a)

no solution

b)

 p=12, p=0p=\frac{1}{2},\ p=0  

c)

 p=−12p=-\frac{1}{2}  

d)

 p=−12, p=0p=-\frac{1}{2},\ p=0  

11.

#21 Solve the absolute value equation:  ∣b7∣+4=5\left|\frac{b}{7}\right|+4=5  


a)

no solution

b)

 b=−7, b=7b=-7,\ b=7  

c)

 b=0, b=7b=0,\ b=7  

d)

 b=7b=7  

12.

#23 Solve for the indicated variable in parenthesis: A=12bh        (h)A=\frac{1}{2}bh\ \ \ \ \ \ \ \ \left(h\right)  


a)

 h=2Abh=\frac{2A}{b}  

b)

 h=2A−bh=2A-b  

c)

 h=12Abh=\frac{1}{2}Ab  

13.

#25 Solve for the indicated variable in parenthesis: a+bk=1        (b)\frac{a+b}{k}=1\ \ \ \ \ \ \ \ \left(b\right)  


a)

 b=ka+1b=\frac{k}{a}+1  

b)

 b=k−ab=k-a  

c)

 b=k+ab=k+a