Free Printable Worksheets
NEW
Font size
More settings
આપેલા સમીકરણયુગ્મનો ઉકેલ શોધો.
2x+3y=13 \frac{2}{x}+\frac{3}{y}=13\ x2+y3=13 & 5x−4y=−2\frac{5}{x}-\frac{4}{y}=-2x5−y4=−2
−12, −13-\frac{1}{2},\ -\frac{1}{3}−21, −31
−12, 13-\frac{1}{2},\ \frac{1}{3}−21, 31
12, −13\frac{1}{2},\ -\frac{1}{3}21, −31
12, 13\frac{1}{2},\ \frac{1}{3}21, 31
2x+5y=1 & 60x+40y=19\frac{2}{x}+\frac{5}{y}=1\ \&\ \frac{60}{x}+\frac{40}{y}=19x2+y5=1 & x60+y40=19
(-4, 10)
(4, 10)
(-4, -10)
(4, -10)
12x+13y=2 & 13x+12y=132\frac{1}{2x}+\frac{1}{3y}=2\ \&\ \frac{1}{3x}+\frac{1}{2y}=\frac{13}{2}2x1+3y1=2 & 3x1+2y1=213
(12, 13)\left(\frac{1}{2},\ \frac{1}{3}\right)(21, 31)
(12, −13)\left(\frac{1}{2},\ -\frac{1}{3}\right)(21, −31)
(−12, 13)\left(-\frac{1}{2},\ \frac{1}{3}\right)(−21, 31)
(−12, −13)\left(-\frac{1}{2},\ -\frac{1}{3}\right)(−21, −31)
2x+3y=17 & 3x+2y=18\frac{2}{x}+\frac{3}{y}=17\ \&\ \frac{3}{x}+\frac{2}{y}=18x2+y3=17 & x3+y2=18
(14, 13)\left(\frac{1}{4},\ \frac{1}{3}\right)(41, 31)
(14, −13)\left(\frac{1}{4},\ -\frac{1}{3}\right)(41, −31)
(−14, 13)\left(-\frac{1}{4},\ \frac{1}{3}\right)(−41, 31)
(−14, −13)\left(-\frac{1}{4},\ -\frac{1}{3}\right)(−41, −31)
4x+y=3xy & 8x+3y=7xy4x+y=3xy\ \&\ 8x+3y=7xy4x+y=3xy & 8x+3y=7xy
(−1, 2)\left(-1,\ 2\right)(−1, 2)
(−1, −2)\left(-1,\ -2\right)(−1, −2)
(1, 2)\left(1,\ 2\right)(1, 2)
View all
10 questions
CÁLCULO MENTAL 6
Worksheet
•
10th Grade
AULÃO
9th - 12th Grade
Tolak ( Berturut-turut) Oleh Ahmad Sokri
1st - 12th Grade
NGHIỆM ĐA THỨC 1 BIẾN
7th - 10th Grade
HOÁN VỊ-CHỈNH HỢP
Examen MatemáticaT 1roBach
Matematika bangun ruang Kelas 6
7th - 12th Grade
分数练习