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Worksheetsmath review (part 3)
Total questions: 16
Worksheet time: 1hrs 29mins
Simplify (3−i)(2i+1)−3i
7+i
5+2i
5+5i
1+7i
if u=<5,−3>, v=<2,6> , find the value of 3v+2u
<16,12>
<19,3>
<12,16>
<3,19>
if u=(3,−4), v=(−2,1) , and w=<−2,4> , find uv−2w
<−1,−3>
<−3,1>
<9,−13>
<−13,9>
Given that z(2i+1)i−3=3i , find the value of 30z
157+15i
7+i
14+i
14+2i
Given that z1=−5−3i, z2=6−i , find the value of z1−z2
(Write in the form <a,b> or (a,b) )
(a)
Given that z1=6+2i, z2=−4+5i , find the value of z2+z1
(Write in the form <a,b> or (a,b) )
(a)
Find the modulus and argument of z when z=−3i+4
∣z∣=5, arg(z)=−36.87°
∣z∣=5, arg(z)=−53.13°
∣z∣=5, arg(z)=36.87°
∣z∣=5, arg(z)=53.13°
express −6−23i in the form z=r(cosθ−isinθ) where −π<θ<π
z=43(cos(65π)+isin(65π))
z=43(cos(67π)+isin(67π))
z=43(cos(−67π)+isin(−67π))
z=43(cos(−65π)+isin(−65π))
express 52(cos(−4π)+isin(−4π))
in the form z=a+bi where a,b∈R (2=1.414, 3=1.732)
(a)
The complex number z is such that ∣z∣=4 and arg(z)=−65π , find z in the form z=a+bi , where a,b∈R
−2−23i
2−23i
−2+23i
2+23i
Solve the equation:
3x2+6x+30=−3
−1+i10
−1−i10
1−i10
1+i10
Given that z=4−3i is one of the root of the equation 2z2−bz+c=0 , where a,b, and c are real constant, find the value of a,b, and c
b=−8, c=25
b=16, c=50
b=−16, c=50
b=8, c=25
Given the function
f(x)=2x3+15x2+Qx−18 , if f(21)=0 , solve for x when f(x)=0
−4±i2
−21
21
4±i2
no answer is correct
Given the equation
Solve for x
1±3i
−1±3i
−1±3i
1
−1
Given the function f(x)=x3+ax2+ax+b , if f(2)=0 and b=−8a ,
(C is complex number)
−3±i7
3±i7
2
3±7i
no answer is correct
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