Free Printable 3. อนุพันธ์ของฟังก์ชันประกอบ

Worksheets

Name

Class

Date

$y=\left(2x+3\right)^5\$ จงหา $\frac{\text{d}y}{\text{d}x}$

$10\left(2x+3\right)$

$10\left(2x+3\right)^4$

$5\left(2x+3\right)^4$

$5\left(2x+3\right)^4\left(2x\right)$

$y=\left(1-3x\right)^3$ จงหา $\frac{\text{d}y}{\text{d}x}$

$3\left(1-3x\right)^2$

$-3\left(1-3x\right)^2$

$-9\left(1-3x\right)^2$

$9\left(1-3x\right)^2$

$y=\sqrt{1-2x}$ จงหา $\frac{\text{d}y}{\text{d}x}$

$-\frac{1}{2\sqrt{1-2x}}$

$\frac{1}{\sqrt{1-2x}}$

$\frac{1}{2\sqrt{1-2x}}$

$-\frac{1}{\sqrt{1-2x}}$

$y=\left(3-4x^2\right)^4$ จงหา $\frac{\text{d}y}{\text{d}x}$

$-32x\left(3-4x^2\right)^3$

$-32\left(3-4x^2\right)^3$

$4\left(3-4x^2\right)^3$

$4x\left(3-4x\right)^3$

$y=\left(2-3x+4x^2\right)^3$ จงหา $\frac{\text{d}y}{\text{d}x}$

$\left(-9+24x\right)\left(2-3x+4x^2\right)^2$

$3\left(2-3x+4x^2\right)^2$

$-9\left(2-3x+4x^2\right)^2$

$-24\left(2-3x+4x^2\right)^2$

$y=\left(x^3-2x\right)^4$ จงหา $\frac{\text{d}y}{\text{d}x}$

$4\left(x^2-2x\right)^3$

$\left(12x^2-8\right)\left(x^3-2x\right)^3$

$\left(x^3-2x\right)^3\left(3x^2-2\right)$

$12\left(x^3-2x\right)^3$

100 %

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