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surface areas and volume

Total questions: 10

Worksheet time: 50mins

Name
Class
Date
1.

Pencil is combination of

a)

cylinder only

b)

cylinder, hemisphere and cone

c)

2 cones and cylinder

d)

cone and cylinder

2.

calculate total surface area of pencil 


(CSA= curved surface area 
TSA= Total surface area )

a)

CSA of Cone+ TSA of Cylinder + CSA of Hemisphere

b)

 CSA of Cone+ TSA of Cylinder 

c)

TSA of Cone+ CSA of Cylinder + TSA of Hemisphere

d)

CSA of Cone+ CSA of Cylinder + CSA of Hemisphere

3.

slant height of this tent is 2.8m. what will be the radius of tent.

a)

2 m

b)

1.4 m

c)

4 m

4.

A cone of radius r is filled with ice- cream such that top of ice cream is hemispherical in shape. if total height of cone is r+h . Find the volume of cream used.

a)

13πr2h+23πr3\frac{1}{3}\pi r^2h+\frac{2}{3}\pi r^3

b)

13πr2(h+r)+23πr3\frac{1}{3}\pi r^2\left(h+r\right)+\frac{2}{3}\pi r^3

c)

13πr2(h+2r)\frac{1}{3}\pi r^2\left(h+2r^{ }\right)

5.

1 liter water is transferred from a beaker to a cube of side 7cm and test tube of radius 2 cm. volume of water will be greater in

a)

cubical box

b)

cylindrical can

c)

will remain same

d)

beaker

6.

During conversion of a solid from one shape to another, the volume of the new shape will

a)

Increases

b)

Decreases

c)

Remain same

d)

Be doubled

7.

 If two solid hemispheres of same base radius r are joined together along their bases, then curved surface area of this new solid is 

a)


 4πr24\pi r^2  

b)

 6πr26\pi r^2  

c)

 8πr28\pi r^2  

d)

 3πr23\pi r^2  

8.

A solid cylinder of radius r and height h is placed over other cylinder of same height and radius. The total surface area of the shape so formed is

a)

4πrh+2πr24πrh+2πr^2

b)

4πrh+4πr24πrh+4πr^2

c)

4πrh4πrh

d)

2πrh+2πr22πrh+2πr^2

9.

 A solid ball is exactly fitted inside the cubical box of side a. The volume of the ball is

a)

 4 3πr2\frac{4\ }{3}\pi r^2  

b)

 1 3πa2\frac{1\ }{3}\pi a^2  

c)

 2 3πa3\frac{2\ }{3}\pi a^3  

d)

 16​πa3\frac{1}{6}​πa^3  

10.

Actual capacity of a vessel as shown in the Fig. (From which hemispherical part is being removed) is equal to the

a)

TSA of the cylinder - CSA of the hemisphere.

b)

volume of the cylinder - volume of the hemisphere.

c)

volume of the cylinder + volume of the hemisphere.

d)

CSA of the cylinder - CSA of the hemisphere.