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Revision Unit 3 A

Total questions: 10

Worksheet time: 5mins

Name
Class
Date
1.

The Fourier Transform of f(x) is  F[f(x)]=F[f(x)]=  

a)

 12π∫−∞∞f(x) dx = F[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)\ dx\ =\ F\left[s\right]  

b)

 12π∫−∞∞f(x)eisx dx = F[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)e^{isx}\ dx\ =\ F\left[s\right]  

c)

 12π∫−∞∞f(x) ds = F[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)\ ds\ =\ F\left[s\right]  

d)

 12π∫−∞∞f(x)  cos⁡sx dx = F[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)\ \ \cos sx\ dx\ =\ F\left[s\right]  

2.

The  inverse Fourier Transform of   F[f(x)] F[f(x)]\  is  f(x) =f\left(x\right)\ =   

a)

 12π∫−∞∞ F[s] dx = f(x)\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}\ F\left[s\right]\ dx\ =\ f\left(x\right)  

b)

 12π∫−∞∞F[s]eisx ds =f(x)\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}F\left[s\right]e^{isx}\ ds\ =f\left(x\right)  

c)

 12π∫−∞∞F[s] e−isxds =f(x)\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}F\left[s\right]\ e^{-isx}ds\ =f\left(x\right)  

d)

 12π∫−∞∞F[s]  cos⁡sx ds = f(x)\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}F\left[s\right]\ \ \cos sx\ ds\ =\ f\left(x\right)  

3.

The Fourier sine Transform of f(x) is  Fs[f(x)]=F_s[f(x)]=  

a)

 12π∫−∞∞f(x) dx = Fs[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)\ dx\ =\ F_s\left[s\right]  

b)

 12π∫0∞f(x) sin⁡sx dx = Fs[s]\frac{1}{\sqrt{2\pi}}\int_0^{\infty}f\left(x\right)\ \sin sx\ dx\ =\ F_s\left[s\right]  

c)

 2π∫0∞f(x) sin⁡sx dx = Fs[s]\sqrt{\frac{2}{\pi}}\int_0^{\infty}f\left(x\right)\ \sin sx\ dx\ =\ F_s\left[s\right]  

d)

 12π∫−∞∞f(x)  cos⁡sx dx = Fs[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)\ \ \cos sx\ dx\ =\ F_s\left[s\right]  

4.

The inverse Fourier sine Transform of   F−1{Fs[f(x)]} = f(x)F^{-1}\left\{F_s[f(x)]\right\}\ =\ f\left(x\right)  

a)

 12π∫−∞∞f(x) ds= Fs[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)\ ds=\ F_s\left[s\right]  

b)

 12π∫0∞ Fs[s]sin⁡sx ds=f(x) \frac{1}{\sqrt{2\pi}}\int_0^{\infty}\ F_s\left[s\right]\sin sx\ ds=f\left(x\right)\   

c)

 2π∫0∞Fs[s]sin⁡sx ds = f(x) \sqrt{\frac{2}{\pi}}\int_0^{\infty}F_s\left[s\right]\sin sx\ ds\ =\ f\left(x\right)\   

d)

 12π∫−∞∞ Fs[s]  cos⁡sx dx =f(x)\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}\ F_s\left[s\right]\ \ \cos sx\ dx\ =f\left(x\right)  

5.

The Fourier cosine Transform of f(x) is  Fc[f(x)]=F_c[f(x)]=  

a)

 12π∫−∞∞f(x) cos⁡sx dx = Fc[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)\ \cos sx\ dx\ =\ F_c\left[s\right]  

b)

 12π∫0∞f(x) cos⁡sx dx = Fc[s]\frac{1}{\sqrt{2\pi}}\int_0^{\infty}f\left(x\right)\ \cos sx\ dx\ =\ F_c\left[s\right]  

c)

 2π∫0∞f(x) cos⁡sx dx = Fc[s]\sqrt{\frac{2}{\pi}}\int_0^{\infty}f\left(x\right)\ \cos sx\ dx\ =\ F_c\left[s\right]  

d)

 12π∫−∞∞f(x)  cos⁡sx dx = Fs[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)\ \ \cos sx\ dx\ =\ F_s\left[s\right]  

6.

The Imaginary part of  e^{isx\ }  is

a)

sinsx

b)

i sinsx

c)

cossx

d)

cosx

7.

The Real part of  e^{isx\ }  is

a)

sinsx

b)

i sinsx

c)

cossx

d)

cosx

8.

The inverse Fourier cosine Transform of   F−1{Fc[f(x)]} = f(x)F^{-1}\left\{F_c[f(x)]\right\}\ =\ f\left(x\right)  

a)

 12π∫−∞∞f(x) cos⁡sx ds= Fc[s]\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}f\left(x\right)\ \cos sx\ ds=\ F_c\left[s\right]  

b)

 2π∫0∞ Fc[s] cos⁡sx  ds=f(x) \sqrt{\frac{2}{\pi}}\int_0^{\infty}\ F_c\left[s\right]\ \cos sx\ \ ds=f\left(x\right)\   

c)

 2π∫0∞Fs[s]sin⁡sx ds = f(x) \sqrt{\frac{2}{\pi}}\int_0^{\infty}F_s\left[s\right]\sin sx\ ds\ =\ f\left(x\right)\   

d)

 12π∫−∞∞ Fs[s]  cos⁡sx dx =f(x)\frac{1}{\sqrt{2\pi}}\int_{-\infty}^{\infty}\ F_s\left[s\right]\ \ \cos sx\ dx\ =f\left(x\right)  

9.

The Fourier Sine Transform of

 e−axe-^{ax}  

a)

 Fs[e−ax]=2π aa2+s2F_s\left[e-^{ax}\right]=\sqrt{\frac{2}{\pi}}\ \frac{a}{a^2+s^2}  

b)

 Fs[e−ax]=2π sa2+s2F_s\left[e^{-ax}\right]=\sqrt{\frac{2}{\pi}}\ \frac{s}{a^2+s^2}  

c)

 Fc[e−ax]=2π sa2+s2F_c\left[e^{-ax}\right]=\sqrt{\frac{2}{\pi}}\ \frac{s}{a^2+s^2}  

d)

none of the above

10.

The Fourier cosine Transform of

 e−axe-^{ax}  

a)

 Fs[e−ax]=2π aa2+s2F_s\left[e-^{ax}\right]=\sqrt{\frac{2}{\pi}}\ \frac{a}{a^2+s^2}  

b)

 Fs[e−ax]=2π sa2+s2F_s\left[e^{-ax}\right]=\sqrt{\frac{2}{\pi}}\ \frac{s}{a^2+s^2}  

c)

 Fc[e−ax]=2π aa2+s2F_c\left[e^{-ax}\right]=\sqrt{\frac{2}{\pi}}\ \frac{a}{a^2+s^2}  

d)

none of the above