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Unit 9A Review

Total questions: 59

Worksheet time: 2hrs 58mins

Name
Class
Date
1.

Find d2ydx2\frac{d^2y}{dx^2} for the parametric equations given by  x(t)=t2+1x\left(t\right)=t^2+1  and  y(t)=t3y\left(t\right)=t^3   

a)

34t\frac{3}{4t}  

b)

32t\frac{3}{2t}  

c)

3t3t  

d)

6t6t  

e)

32\frac{3}{2}  

2.

Consider the curve in the xy plane represented by x=etx=e^t  and  y=te−ty=te^{-t}  for  t≥0t\ge0  .  The slope of the tangent to the curve at the point when x=3 (not t=3) is...

a)

20.086

b)

0.342

c)

-0.005

d)

-0.011

e)

-0.03

3.

The flight of a paper airplane is modeled by the curve given by x=t−3sin⁡tx=t-3\sin t and  y=4−3cos⁡ty=4-3\cos t for time t in seconds and  0≤t≤100\le t\le10 (x and y are in feet). What is the distance traveled by the paper airplane?

a)

31.343 feet

b)

20.076 feet

c)

49.229 feet

d)

68.930 feet

4.

The flight of a paper airplane is modeled by the curve given by x=t−3sin⁡tx=t-3\sin t and  y=4−3cos⁡ty=4-3\cos t for time t in seconds and  0≤t≤100\le t\le10 (x and y are in feet). What describes the motion of the paper airplane at t=7 seconds?

a)

Up and to the right

b)

Down and to the right

c)

Up and to the left

d)

Down and to the left

5.

The flight of a paper airplane is modeled by the curve given by x=t−3sin⁡tx=t-3\sin t and  y=4−3cos⁡ty=4-3\cos t for time t in seconds and  0≤t≤100\le t\le10 (x and y are in feet). What is the slope of the tangent line to the path of the paper airplane at t=7 seconds?

a)

-0.185

b)

-0.640

c)

-1.562

d)

-5.409

6.

Consider the curve given by x=t3+2t−1x=t^3+2t-1  and  y=t2−t+5y=t^2-t+5 .  What is the arc length of the curve for  0≤t≤20\le t\le2  ? 

a)

12.278

b)

4.960

c)

13.230

d)

5.619

7.

A curve in the plane is defined by x=t3+tx=t^3+t and y=t4+2t2y=t^4+2t^2 .  An equation of the tangent line to the curve at t=1 is... 

a)

 y=2x−1y=2x-1  

b)

 y=2xy=2x  

c)

 y=4x−5y=4x-5  

d)

 y=8xy=8x  

e)

 y=8x+13y=8x+13  

8.

Find dydx\frac{dy}{dx} for the curve given by x=(t−1)3x=\left(t-1\right)^3 and y=ty=\sqrt{t} . 

a)

 3(t−1)23\left(t-1\right)^2  

b)

 16t(t−1)2\frac{1}{6\sqrt{t}\left(t-1\right)^2}  

c)

 6(t−1)2t\frac{6\left(t-1\right)^2}{\sqrt{t}}  

d)

 6t(t−1)26\sqrt{t}\left(t-1\right)^2  

9.

The length of the curve determined by x=t2x=t^2 and  y=ty=t  from t=0 to t=4 is

a)

 ∫044t+1dt\int_0^4\sqrt{4t+1}dt  

b)

 2∫04t2+1dt2\int_0^4\sqrt{t^2+1}dt  

c)

 ∫042t2+1dt\int_0^4\sqrt{2t^2+1}dt  

d)

 ∫044t2+1dt\int_0^4\sqrt{4t^2+1}dt  

e)

 2π∫044t2+1dt2\pi\int_0^4\sqrt{4t^2+1}dt  

10.

Find the equation of the tangent line for the curve defined by x=2tx=2t and y=t2+5y=t^2+5 at the point where t=2. 

a)

 y=2x+1y=2x+1  

b)

 y=2x+5y=2x+5  

c)

 y=x+4y=x+4  

d)

 y=x−4y=x-4  

11.

Consider the curve given by x=2sin⁡tx=2\sin t and  y=4cos⁡2ty=4\cos^2t for  0≤t≤π0\le t\le\pi .  Find  d2ydx2\frac{d^2y}{dx^2}  at  t=π4t=\frac{\pi}{4}  

a)

 −22-\frac{\sqrt{2}}{2}  

b)

 −2-2  

c)

 22\frac{\sqrt{2}}{2}  

d)

 22  

12.

Find the slope at the value t=3 for the parametric equations x=t+10x=t+10 and  y=t2+2ty=t^2+2t  

a)

8

b)

-4

c)

27/2

d)

4

e)

-27/2

13.

Find the concavity at the value t=3 for the parametric equations x=t+10x=t+10 and  y=t2+2ty=t^2+2t  

a)

concave up

b)

concave down

c)

inflection point

14.

Find all points of horizontal tangency to the curve x=7+3cos⁡tx=7+3\cos t  and  y=−5+sin⁡ty=-5+\sin t  

a)

(7,-5)

b)

(4,-5)

c)

(7,-4)

d)

(7,-6)

15.

If r(t)=<5t2−2t,3−ln⁡t>r\left(t\right)=<5t^2-2t,3-\ln t> , then  −13r′(2)=-\frac{1}{3}r'\left(2\right)=   

a)

<18,12><18,\frac{1}{2}>  

b)

<18,−12><18,-\frac{1}{2}>  

c)

<−6,−16><-6,-\frac{1}{6}>  

d)

<−6,16><-6,\frac{1}{6}>  

16.

Given r′(t)=<te−t2,−e−t>r'\left(t\right)=<te^{-t^2},-e^{-t}> and  r(0)=<12,−1>r\left(0\right)=<\frac{1}{2},-1> find r(t) that satisfies the initial condition.  

a)

<2−e−t2,e−t−2><2-e^{-t^2},e^{-t}-2>  

b)

<2−e−t2,e−t><2-e^{-t^2},e^{-t}>  

c)

<2−e−t22,e−t><\frac{2-e^{-t^2}}{2},e^{-t}>  

d)

<2−e−t22,e−t−2><\frac{2-e^{-t^2}}{2},e^{-t}-2>  

17.

If r(t)=<e−4t+9,7−4t3>r\left(t\right)=<e^{-4t}+9,7-4t^3> , then r"(t)= 

a)

<e−4t,−12t2><e^{-4t},-12t^2>  

b)

<−4e−4t,−12t2><-4e^{-4t},-12t^2>  

c)

<16e−4t,−24t><16e^{-4t},-24t>  

d)

<e−4t,−24t><e^{-4t},-24t>  

18.

If dRdt=<32t+1,e−t>\frac{dR}{dt}=<\frac{3}{2}\sqrt{t+1},e^{-t}> where R(0)=<0,0>R\left(0\right)=<0,0>  , find R(t)R\left(t\right) . 

a)

<(t+1)32,−e−t><\left(t+1\right)^{\frac{3}{2}},-e^{-t}>  

b)

<(t+1)32−1,−[e−t−1]><\left(t+1\right)^{\frac{3}{2}}-1,-\left[e^{-t}-1\right]>  

c)

<(t+1)12−1,−[e−t−1]><\left(t+1\right)^{\frac{1}{2}}-1,-\left[e^{-t}-1\right]>  

d)

<(t+1)32+1,−[e−t+1]><\left(t+1\right)^{\frac{3}{2}}+1,-\left[e^{-t}+1\right]>  

19.

∫02<et,−tet>dt=\int_0^2<e^t,-te^t>dt=  

a)

<e2−1,−e2−1><e^2-1,-e^2-1>  

b)

<e2−1,−e2><e^2-1,-e^2>  

c)

<e2,−e2−1><e^2,-e^2-1>  

d)

<e2−1,e2+1><e^2-1,e^2+1>  

20.

For t≥0t\ge0 , a particle moves along a curve so that its position at time t is given by (x(t),y(t)).  At t=3, the particle is at position (6,2).  Given dxdt=1−cos⁡2t\frac{dx}{dt}=1-\cos^2t and  dydt=t1.51.2t\frac{dy}{dt}=\frac{t^{1.5}}{1.2^t} , is the vertical movement of the particle up or down at t=3? 

a)

Up

b)

Down

21.

For t≥0t\ge0 , a particle moves along a curve so that its position at time t is given by (x(t),y(t)).  At t=3, the particle is at position (6,2).  Given dxdt=1−cos⁡2t\frac{dx}{dt}=1-\cos^2t and  dydt=t1.51.2t\frac{dy}{dt}=\frac{t^{1.5}}{1.2^t} , find the y-coordinate of the particle's position at t=5

a)

9.644

b)

8.352

c)

7.123

d)

8.857

22.

For t≥0t\ge0 , a particle moves along a curve so that its position at time t is given by (x(t),y(t)).  At t=3, the particle is at position (6,2).  Given dxdt=1−cos⁡2t\frac{dx}{dt}=1-\cos^2t and  dydt=t1.51.2t\frac{dy}{dt}=\frac{t^{1.5}}{1.2^t} , find the speed of the particle at t=5.

a)

4.586

b)

3.186

c)

3.975

d)

5.184

23.

For t≥0t\ge0 , a particle moves along a curve so that its position at time t is given by (x(t),y(t)).  At t=3, the particle is at position (6,2).  Given dxdt=1−cos⁡2t\frac{dx}{dt}=1-\cos^2t and  dydt=t1.51.2t\frac{dy}{dt}=\frac{t^{1.5}}{1.2^t} , find the distance traveled by the particle from time t=3 to t=5.

a)

7.746

b)

8.512

c)

9.149

d)

9.867

24.

The position of a particle moving in the xy-plane is given by (x(t),y(t)) for which x′(t)=tsin⁡tx'\left(t\right)=t\sin t and y′(t)=5e−3t+2y'\left(t\right)=5e^{-3t}+2 .  What is the slope of the line tangent to the path of the particle at the point at which t=2? 

a)

0.904

b)

1.107

c)

1.819

d)

2.012

e)

3.660

25.

The position of a particle moving in the xy-plane is given by x(t)=t3−3t2x\left(t\right)=t^3-3t^2  and  y(t)=12t−3t2y\left(t\right)=12t-3t^2 .  At which point is the particle at rest? 

a)

(-4,12)

b)

(-3,6)

c)

(-2,9)

d)

(0,0)

e)

(3,4)

26.

The position of a particle moving along a curve at time

t≥0t\ge0  is given by the parametric equations (x(t),y(t)) where  x(t)=3t−5x\left(t\right)=3t-5 and y(t)=t2+3t−28y\left(t\right)=t^2+3t-28  .  What is the slope of the tangent line to the curve at t=6?

a)

2

b)

3

c)

5

d)

15

27.

For t≥0t\ge0 , a particle is moving along a curve so that its position at time t is given by the parametric equations  x(t)=sin⁡tx\left(t\right)=\sin t  and  y(t)=t2−t+3y\left(t\right)=t^2-t+3  .  Which of the following expressions gives the speed of the particle at time t? 

a)

sin⁡t+(t2−t+3)\sqrt{\sin t+\left(t^2-t+3\right)}  

b)

cos⁡t+(2t−1)\sqrt{\cos t+\left(2t-1\right)}  

c)

sin⁡2t+(t2−t+3)2\sqrt{\sin^2t+\left(t^2-t+3\right)^2}  

d)

cos⁡2t+(2t−1)2\sqrt{\cos^2t+\left(2t-1\right)^2}  

28.

At time t, a particle moving along a curve in the xy-plane has position (x(t), y(t)) where x(t)=sin⁡(πt3)x\left(t\right)=\sin\left(\frac{\pi t}{3}\right)  and  y(t)=t2−5y\left(t\right)=t^2-5  .  Which of the following gives the direction of motion for the particle at t=2?

a)

Up and to the right

b)

Up and to the left

c)

Down and to the right

d)

Down and to the left

29.

For t≥0t\ge0 , a particle is moving along a curve so that its position at time t is given by the parametric relations x(t) (the graph) and  y(t)=t2−3t+1y\left(t\right)=t^2-3t+1 .  Which of the following expressions gives the total distance the particle travels on the interval [0,4]

a)

∫04(−1)2+(2t−3)2dt\int_0^4\sqrt{\left(-1\right)^2+\left(2t-3\right)^2}dt  

b)

∫04(−1)2+(t2−3t+1)2dt\int_0^4\sqrt{\left(-1\right)^2+\left(t^2-3t+1\right)^2}dt  

c)

∫02(−2)2+(2t−3)2dt\int_0^2\sqrt{\left(-2\right)^2+\left(2t-3\right)^2}dt  + ∫24(0)2+(2t−3)2dt\int_2^4\sqrt{\left(0\right)^2+\left(2t-3\right)^2}dt  

d)

∫02(−2)2+(t2−3t+1)2dt\int_0^2\sqrt{\left(-2\right)^2+\left(t^2-3t+1\right)^2}dt  + ∫24(0)2+(t2−3t+1)2dt\int_2^4\sqrt{\left(0\right)^2+\left(t^2-3t+1\right)^2}dt  

30.

A curve is defined parametrically by the equations x(t)=3tx\left(t\right)=3\sqrt{t} and y(t)=14t2y\left(t\right)=\frac{1}{4}t^2 .  Which of the following represents the equation of the line tangent to the curve at t=4? 

a)

y=83xy=\frac{8}{3}x  

b)

y=4+83(x−6)y=4+\frac{8}{3}\left(x-6\right)  

c)

y=4+16(x−6)y=4+\frac{1}{6}\left(x-6\right)  

d)

y=4+43(x−6)y=4+\frac{4}{3}\left(x-6\right)  

31.

For what value(s) of t does the curve defined by the parametric equations x=4t3−2t2−4x=\frac{4}{t^3-2t^2-4} and  y=2t+18t2y=\frac{2}{t}+\frac{1}{8}t^2 have a horizontal tangent?  

a)

0

b)

2

c)

0 and 4/3

d)

4/3 and 2

32.

The position of a particle moving in the xy-plane is given by the parametric equations x(t)=2cos⁡tx\left(t\right)=2^{\cos t} and y(t)=2sin⁡ty\left(t\right)=2^{\sin t}  for time t≥0t\ge0 .  What is the speed of the particle when t=1.2?  

a)

0.919

b)

0.959

c)

2.301

d)

5.293

33.

At t≥0t\ge0 , a particle moving in the xy-plane has a position vector given by r(t)=<t2−t+4,e2t−10>r\left(t\right)=<t^2-t+4,e^{2t-10}> .  What is the speed of the particle at time t=5? 

a)

252\sqrt{5}  

b)

82\sqrt{82}  

c)

85\sqrt{85}  

d)

577\sqrt{577}  

34.

An object moves in the xy-plane so that its position at any time t is given by the parametric equations x(t)=e2tx\left(t\right)=e^{2t} and y(t)=2t3−t2+4y\left(t\right)=2t^3-t^2+4 .  What is the slope of the tangent line at t=2? 

a)

10e4\frac{10}{e^4}  

b)

e410\frac{e^4}{10}  

c)

20e4\frac{20}{e^4}  

d)

16e4\frac{16}{e^4}  

35.

Find the arc length of the curve defined by x=arcsin⁡t, y=ln⁡1−t2x=\arcsin t,\ y=\ln\sqrt{1-t^2}  on the interval  0≤t≤120\le t\le\frac{1}{2}  

a)

0.549

b)

0.836

c)

1.247

d)

0.333

36.

Find dy/dx for the graph of the parametric equations

x=t2,y=t2+6t+5x=t^2,y=t^2+6t+5  

a)

tt+6\frac{t}{t+6}  

b)

1+3t1+\frac{3}{t}  

c)

1+t31+\frac{t}{3}  

d)

t+6t\frac{t+6}{t}  

37.

Find  d2ydx2\frac{d^2y}{dx^2}  for the graph of the parametric equations

x=t2,y=t2+6t+5x=t^2,y=t^2+6t+5  

a)

−32t3\frac{-3}{2t^3}  

b)

−6t-\frac{6}{t}  

c)

−3t2-\frac{3}{t^2}  

d)

−32t-\frac{3}{2t}  

38.

Find  dydx\frac{dy}{dx}  for the graph of the parametric equations

x=t,y=3t2+2tx=\sqrt{t},y=3t^2+2t  

a)

3t+1t3\sqrt{t}+\frac{1}{\sqrt{t}}  

b)

12t3+4t12\sqrt{t^3}+4\sqrt{t}  

c)

tt+1\frac{\sqrt{t}}{t+1}  

d)

6t3+2t6\sqrt{t^3}+2\sqrt{t}  

39.

Find  d2ydx2\frac{d^2y}{dx^2}  for the graph of the parametric equations

x=t,y=3t2+2tx=\sqrt{t},y=3t^2+2t  

a)

36t+436t+4  

b)

9+1t9+\frac{1}{t}  

c)

18t+2t18\sqrt{t}+\frac{2}{\sqrt{t}}  

d)

9t+19t+1  

40.

Find  dydx\frac{dy}{dx}  for the graph of the parametric equations

x=ln⁡t ,y=t2+tx=\ln t\ ,y=t^2+t  

a)

2t2+t2t^2+t  

b)

2+1t2+\frac{1}{t}  

c)

12t2+t\frac{1}{2t^2+t}  

d)

2t+12t+1  

41.

Find  d2ydx2\frac{d^2y}{dx^2}  for the graph of the parametric equations

x=ln⁡t ,y=t2+tx=\ln t\ ,y=t^2+t  

a)

4t+14t+1  

b)

4+1t4+\frac{1}{t}  

c)

4t2+t4t^2+t  

d)

4t+1ln⁡t\frac{4t+1}{\ln t}  

42.

For the curve defined by the parametric equations x=2cos⁡t, y=3sin⁡tx=2\cos t,\ y=3\sin t , find the tangent line where  t=π4t=\frac{\pi}{4}  

a)

(y−322)=−32(x−2)\left(y-\frac{3\sqrt{2}}{2}\right)=-\frac{3}{2}\left(x-\sqrt{2}\right)  

b)

(y−2)=−32(x−322)\left(y-\sqrt{2}\right)=-\frac{3}{2}\left(x-\frac{3\sqrt{2}}{2}\right)  

c)

(y−322)=32(x−2)\left(y-\frac{3\sqrt{2}}{2}\right)=\frac{3}{2}\left(x-\sqrt{2}\right)  

d)

(y−2)=32(x−322)\left(y-\sqrt{2}\right)=\frac{3}{2}\left(x-\frac{3\sqrt{2}}{2}\right)  

43.

Given the parametric equations x=t2−t+1, y=t3−3tx=t^2-t+1,\ y=t^3-3t , find the point(s) where the curve has a horizontal tangent. 

a)

(1,-2)

b)

(3,2)

c)

(-3,2)

d)

(1,2)

44.

Given the parametric equations x=t2−t+1, y=t3−3tx=t^2-t+1,\ y=t^3-3t , find the point(s) where the curve has a vertical tangent. 

a)

(34,−118)\left(\frac{3}{4},-\frac{11}{8}\right)  

b)

(34,138)\left(\frac{3}{4},\frac{13}{8}\right)  

c)

(74,−118)\left(\frac{7}{4},-\frac{11}{8}\right)  

d)

(74,138)\left(\frac{7}{4},\frac{13}{8}\right)  

45.

Given the parametric equations x=3+2cos⁡t, y=−1+4sin⁡tx=3+2\cos t,\ y=-1+4\sin t , find the point(s) where the curve has a vertical tangent. 

a)

(5,-1)

b)

(1,-1)

c)

(3,3)

d)

(3,-5)

46.

What is the arc length of the curve created by the parametric equations x=t2, y=t3, 0≤t≤2x=t^2,\ y=t^3,\ 0\le t\le2  

a)

9.073

b)

12

c)

5.506

d)

15.027

47.

What is the arc length of the curve created by the parametric equations x=e2t+1, y=3t−1, −2≤t≤2x=e^{2t}+1,\ y=3t-1,\ -2\le t\le2  

a)

∫−224e4t+9dt\int_{-2}^2\sqrt{4e^{4t}+9}dt  

b)

∫−22e4t+9dt\int_{-2}^2\sqrt{e^{4t}+9}dt  

c)

∫−222e4t+9dt\int_{-2}^2\sqrt{2e^{4t}+9}dt  

d)

∫−224e2t+9dt\int_{-2}^2\sqrt{4e^{2t}+9}dt  

48.

Identify the curve of x=2t+1, y=t2+2x=2t+1,\ y=t^2+2 .

a)

A

b)

B

c)

C

d)

D

49.

At time t on [0,2], the velocity of a particle moving along the x-axis is given by v(t)=et2−2v\left(t\right)=e^{t^2}-2 .  What is the total distance traveled by the particle during the time interval [0,2]? 

a)

12.453

b)

13.638

c)

51.598

d)

53.598

50.

The velocity of a particle moving in a straight line for t≥0t\ge0  is given by  v(t)=ln⁡(t3+1)v\left(t\right)=\ln\left(t^3+1\right)  .  What is the acceleration of the particle at t=4?

a)

0.738

b)

3.436

c)

4.174

d)

8.232

51.

At time t≥0t\ge0 , a particle moving in the xy-plane has velocity vector given by v(t)=<4e−t,sin⁡(1+t)>v\left(t\right)=<4e^{-t},\sin\left(1+\sqrt{t}\right)> .  What is the total distance the particle travels between t=1 and t=3? 

a)

1.861

b)

1.983

c)

2.236

d)

4.851

52.

For time t≥0t\ge0 seconds, the position of an object traveling along a curve in the xy-plane is given by the parametric equations x(t) and y(t), where dxdt=t2+3\frac{dx}{dt}=t^2+3 and dydt=t3+t\frac{dy}{dt}=t^3+t .  At what time t is the speed of the object 10 units per second? 

a)

1.675

b)

1.813

c)

4.217

d)

10.191

53.

At time t>0, the position of a particle moving along a curve in the xy-plane is (x(t),y(t)) where dxdt=t−5cos⁡t\frac{dx}{dt}=t-5\cos t and dydt=6cos⁡(1+sin⁡t)\frac{dy}{dt}=6\cos\left(1+\sin t\right) .  At time t=3, the particle is at position (-1,2). What is the equation of the tangent line to the path of the particle at t=3? 

a)

y=0.314x+2.314y=0.314x+2.314  

b)

y=0.314x+2.686y=0.314x+2.686  

c)

y=−3.010x−1.010y=-3.010x-1.010  

d)

y=−3.010x+5.010y=-3.010x+5.010  

54.

At time t>0, the position of a particle moving along a curve in the xy-plane is (x(t),y(t)) where dxdt=t−5cos⁡t\frac{dx}{dt}=t-5\cos t and dydt=6cos⁡(1+sin⁡t)\frac{dy}{dt}=6\cos\left(1+\sin t\right) .  At time t=3, the particle is at position (-1,2).

Find the time where the path of the particle is vertical.  Is the motion up or down at that moment?

a)

t=1.306, moving up

b)

t=1.306, moving down

c)

t=0.607, moving up

d)

t=0.607, moving down

55.

At time t>0, the position of a particle moving along a curve in the xy-plane is (x(t),y(t)) where dxdt=t−5cos⁡t\frac{dx}{dt}=t-5\cos t and dydt=6cos⁡(1+sin⁡t)\frac{dy}{dt}=6\cos\left(1+\sin t\right) .  At time t=3, the particle is at position (-1,2). Find the y-coordinate of the particle's position at t=0.

a)

3.634

b)

-1.794

c)

0.634

d)

-4.794

56.

At time t>0, the position of a particle moving along a curve in the xy-plane is (x(t),y(t)) where dxdt=t−5cos⁡t\frac{dx}{dt}=t-5\cos t  and dydt=6cos⁡(1+sin⁡t)\frac{dy}{dt}=6\cos\left(1+\sin t\right) .   At time t=3, the particle is at position (-1,2).

Find the total distance traveled by the particle for [0,3].

a)

13.453

b)

16.812

c)

17.995

d)

15.002

57.

For t>0, a particle is moving along a curve so that its position at time t is ((x(t),y(t)).  At time t=2, the particle is at position (1,5).  It is known that dxdt=t+2et\frac{dx}{dt}=\frac{\sqrt{t+2}}{e^t} and dydt=sin⁡2t\frac{dy}{dt}=\sin^2t .  Find the x-coordinate of the particle's position at time t=4.

a)

1.253

b)

1.485

c)

1.111

d)

1.321

58.

For t>0, a particle is moving along a curve so that its position at time t is ((x(t),y(t)).  At time t=2, the particle is at position (1,5).  It is known that dxdt=t+2et\frac{dx}{dt}=\frac{\sqrt{t+2}}{e^t} and dydt=sin⁡2t\frac{dy}{dt}=\sin^2t .  Find the speed of the particle at t=4.

a)

0.575

b)

1.899

c)

0.332

d)

0.136

59.

For t>0, a particle is moving along a curve so that its position at time t is ((x(t),y(t)).  At time t=2, the particle is at position (1,5).  It is known that dxdt=t+2et\frac{dx}{dt}=\frac{\sqrt{t+2}}{e^t} and dydt=sin⁡2t\frac{dy}{dt}=\sin^2t .  Find the y component of the acceleration vector at t=4.

a)

-0.041

b)

0.989

c)

1.234

d)

3.005