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Tg 45°
2
1
4/3
3/4
5
7
4
Halla T =4csc245°−tan45°Halla\ \ T\ =4\csc^245°-\sqrt{\tan45°}Halla T =4csc245°−tan45°
6
(tan45°+cot45°)2−2csc245°\left(\tan45°+\cot45°\right)^2-2\csc^245°(tan45°+cot45°)2−2csc245°
0
6sec45°csc45° - 9tan45°
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(1sec45°+1csc45°)2\left(\frac{1}{\sec45°}+\frac{1}{\csc45°}\right)^2(sec45°1+csc45°1)2
1/2
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(sec45°.csc45°)2tan45°\left(\sec45°.\csc45°\right)^{2\tan45°}(sec45°.csc45°)2tan45°
8tan245°2csc245°\frac{8\tan^245°}{2\csc^245°}2csc245°8tan245°
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10 questions
EXAMEN DE GEOMETRIA TERCER PERIODO- 5º1
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