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Worksheets

Limits (infinite limits, limits at infinity & continuity)

Total questions: 22

Worksheet time: 2hrs 50mins

Name
Class
Date
1.

Evaluate the limit.

a)

\infty

b)

-\infty

c)

11

d)

DNE

2.

Evaluate the limit.

a)

\infty

b)

-\infty

c)

0

d)

DNE

3.

Evaluate the limit.

a)

\infty

b)

-\infty

c)

0

d)

DNE

4.

What is the limit as x approaches 2?

a)

0

b)

4

c)

14\frac{1}{4}

d)

DNE

5.

What is the limit as -2 from the left?

a)

 \infty  

b)

 -\infty  

c)

0

d)

 14-\frac{1}{4}  

6.

Identify the vertical asymptote(s) in the function above. (Hint: The last three problems used this same function.)

a)

x=2x=2

b)

x=±2x=\pm2

c)

x=2x=-2

d)

There are no vertical asymptotes.

7.

What is the limit of the function?

a)

\infty

b)

-\infty

c)

0

d)

DNE

8.

What is the limit of the function?

a)

\infty

b)

-\infty

c)

0

d)

DNE

9.

What is the limit of the function?

a)

\infty

b)

-\infty

c)

0

d)

DNE

10.
a)

\infty

b)

-\infty

c)

0

d)

DNE

11.

Evaluate the limit.

a)

\infty

b)

-\infty

c)

0

d)

5

12.

Evaluate the limit.

a)

\infty

b)

-\infty

c)

0

d)

5

13.

Identify the horizontal asymptote(s). (Hint: The last two question used the same function.)

a)

 y=5y=5  

b)

 y=5y=-5  

c)

 y=±5y=\pm5  

d)

There are no horizontal asymptotes.

14.

Identify the discontinuities in the function.

a)

x=1, 2, 3, 4, 5, 6x=1,\ 2,\ 3,\ 4,\ 5,\ 6

b)

x=2, 3, 4, 5, 6x=2,\ 3,\ 4,\ 5,\ 6

c)

x=2, 3, 4, 5x=2,\ 3,\ 4,\ 5

d)

x=2, 3, 4x=2,\ 3,\ 4

15.

Which discontinuities violate the first condition? Condition 1: f(a) is defined​ (a is in the domain of​ f).

a)

x=3x=3

b)

x=2, 3x=2,\ 3

c)

x=2, 3, 4x=2,\ 3,\ 4

d)

x=2, 4x=2,\ 4

16.

Which discontinuities violate the second condition? (Condition 2: The limit as x approaches a exists.)

a)

x=2, 3x=2,\ 3

b)

x=2, 3, 4x=2,\ 3,\ 4

c)

x=2, 4x=2,\ 4

d)

x=3, 4x=3,\ 4

17.

Which discontinuities violate the third condition? (Condition 3: The value of f equals the limit of f at​ a.)

a)

x=2, 3, 4x=2,\ 3,\ 4

b)

x=2, 3x=2,\ 3

c)

x=3, 4x=3,\ 4

d)

x=2, 4x=2,\ 4

18.

For which values is the function below continuous?
 f(x)=2x3+x+2f\left(x\right)=2x^3+x+2  

a)

It is continuous on ​[−1​,0​], but not for all x.

b)

It is continuous for some​ x, but not on ​[−1​,0​].

c)

It is continuous for all x.

d)

It is not continuous on any interval.

19.

 f(x)=2x3+x+2; (1, 0)f\left(x\right)=2x^3+x+2;\ \left(-1,\ 0\right)  

What is the value at the left endpoint?

a)

2

b)

-1

c)

0

d)

1

20.

 f(x)=2x3+x+2; (1, 0)f\left(x\right)=2x^3+x+2;\ \left(-1,\ 0\right)  
What is the value at the right endpoint?

a)

-1

b)

0

c)

1

d)

2

21.

Can the Intermediate Value Theorem be used to show that f(x) has a solution on (-1, 0)? (Hint: The last two questions can be used to help answer this.)
 f(x)=2x3+x+2f\left(x\right)=2x^3+x+2  

a)

It can be used because the function is defined on ​(−1​,0​) and 0<​f(−1​)<​f(0​).

b)

It can be used because the function is continuous on ​[−1​,0​] and the function is defined at x=−1 and x=0.

c)

It can be used because the function is defined on ​(−1​,0​) and ​f(−1​)<​f(0​)<0.

d)

It can be used because the function is continuous on ​[−1​,0​] and 0 is between ​f(−1​) and ​f(0​).

22.

 f(x)=2x3+x+2f\left(x\right)=2x^3+x+2  

There​ is/are a​ solution(s) to the equation in ​(−1​,0​) at 

a)

 x2.235x\approx2.235  

b)

 x0.835x\approx-0.835  

c)

 x0.835, 2.235x\approx-0.835,\ 2.235  

d)

There is not a solution in (-1, 0)