wayground logo

Free Printable Worksheets

Font size

S
M
L
XL
Worksheets

The area bounded by a polar curve

Total questions: 8

Worksheet time: 24mins

Name
Class
Date
1.

The area bounded by the spiral

 r=aθπr=\frac{a\theta}{\pi}  from  θ=0 to θ=π\theta=0\ to\ \theta=\pi  and the initial line is

a)

 12πa2\frac{1}{2}\pi a^2  

b)

 13πa2\frac{1}{3}\pi a^2  

c)

 πa2\pi a^2  

d)

 16πa2\frac{1}{6}\pi a^2  

2.

The area bounded by the spiral r=aθπr=\frac{a\theta}{\pi}  from  θ=0 \theta=0\  to  θ=2π\theta=2\pi   and the initial line is


a)

 13πa2\frac{1}{3}\pi a^2  

b)

 23πa2\frac{2}{3}\pi a^2  

c)

 43πa2\frac{4}{3}\pi a^2  

d)

 πa2\pi a^2  

3.

The area enclosed by one loop of the curve

 r2=cos3θr^2=\cos3\theta 

 is

a)

 16π\frac{1}{6}\pi  

b)

 13π\frac{1}{3}\pi  

c)

 16\frac{1}{6}  

d)

 13\frac{1}{3}  

4.

The area of the cardioid

 r=2(1+cosθ)r=2\left(1+\cos\theta\right)  
is

a)

 3π3\pi  

b)

 12π12\pi  

c)

 2π2\pi  

d)

 6π6\pi  

5.

The area of one loop of the curve

 r=asin4θr=a\sin4\theta  
is

a)

 12πa2\frac{1}{2}\pi a^2  

b)

 18πa2\frac{1}{8}\pi a^2  

c)

 14πa2\frac{1}{4}\pi a^2  

d)

 116πa2\frac{1}{16}\pi a^2  

6.

A curve, C, has a polar equation

 r=e3θ, 0 θ0.5r=e^{3\theta},\ 0\ \le\theta\le0.5 
The area of the region bounded by C and the lines  θ=0 \theta=0\   and  θ=0.5\theta=0.5  , correct to 3 s.f., 

is

a)

2.68

b)

1.67

c)

1.59

d)

4.95

7.

The area bounded by the curve r=1+2cosθ r=1+\sqrt{2}\cos\theta\  

 is


a)

 32π+32\frac{3}{2}\pi+\frac{3}{2}  

b)

 3π+33\pi+3  

c)

 32π+52\frac{3}{2}\pi+\frac{5}{2}  

d)

 3π+53\pi+5  

8.

A curve C has polar equation  r=2cosθ.r=2\cos\theta.   A curve D has polar equation r = 1 . The line  θ=0\theta=0  intersects C at the point A and D at the point P.

The line  θ=π6\theta=\frac{\pi}{6}  intersects C at the point B and D at the point Q. 


The area of the region bounded by the arcs PQ and AB and the lines  θ=0\theta=0  and  θ=π6\theta=\frac{\pi}{6}  is

a)

 316+7π24\frac{\sqrt{3}}{16}+\frac{7\pi}{24}  

b)

 148(14π+48+33)\frac{1}{48}\left(14\pi+48+3\sqrt{3}\right)  

c)

 116(2π+8+3)\frac{1}{16}\left(2\pi+8+\sqrt{3}\right)  

d)

 π148(15+83)\frac{\pi1}{48}\left(15+8\sqrt{3}\right)