Yes, the relationship above is a function.

No, the relationship above is not a function

It cannot be determined whether the relationship is a function or not a function

-5

4

3

Does not exist

1

-1

-5

Does not exist

f(x)= (x+2)(x+6)(x-5)

f(x)=(x-2)(x-6)(x+5)

f(x)=(x-2)(x-6)(x-5)

f(x)=(x-2)(x-6)(x+5)

f(x)=x(x+7)

f(x)=x(x-3.5)

f(x)=x(x-7)

f(x)=-x(x-7)

$As\ x\rightarrow-\infty,\ y\rightarrow\infty$ and $As\ x\rightarrow\infty\ ,\ y\ \rightarrow-\infty$

$As\ x\rightarrow\infty,\ y\rightarrow\infty$ and $As\ x\rightarrow\infty,\ y\ \rightarrow\infty$

$As\ x\rightarrow-\infty,\ y\rightarrow-\infty$ and $As\ x\rightarrow\infty\ ,\ y\rightarrow-\infty$

0

-3

4

-12

$\frac{-3\pm\sqrt{73}}{4}$

$\frac{3\pm\sqrt{73}}{4}$

$\frac{-3}{4}$

$\frac{3}{4}$

$y=3^x$

$y=4\left(3^x\right)$

$y=3\left(4^x\right)$

$y=4^x$

y = 20 (4^x)

y = 4 (20^x)

y = 4^x

y = 20^x

0

1

2

3

0

1

2

3

0

1

2

3

log x⁴ - log y

log x⁴ + log y

log x + 4 log y

4 log + log y