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Mole Conversions

Total soal: 13

Worksheet time: 37mins

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1.

What is the molar mass of a substance?

a)

The mass of one atom of that substance.

b)

The mass of one mole of that substance in grams.

c)

The mass of one mole of a substance in atomic mass units (amu).

d)

The mass of a substance in mg.

2.

Where can you find the molar mass of a substance?

a)

Looking up the average atomic mass on a periodic table.

b)

Looking up the atomic number on a periodic table.

c)

Looking up the conversion factor for one mole which is 1 mole = 6.02223 items.

d)

Looking up the metric prefixes chart.

3.

What are the units of molar mass?

a)

mol

b)

g

c)

g/mol

d)

mol/g

e)

amu

4.

What is the molar mass of carbon?

a)

6 amu

b)

6 g/mol

c)

12.01 amu

d)

12.01 g/mol

5.

What is the molar mass of MgCl2?

a)

24.31 g/mol

b)

59.76 g/mol

c)

95.21 g/mol

d)

119.52 g/mol

6.

(Hint: write out how you would solve the problem first on paper before choosing an answer.) 



How would you set up the problem if you have a sample of 2.50 g of sodium (Na), how many moles of Na do you have?

a)

 2.50g Na ×22.99 mol Na1 g Na=2.50g\ Na\ \times\frac{22.99\ mol\ Na}{1\ g\ Na}=  

b)

 2.50 g Na ×1 mol Na22.99 g Na=2.50\ g\ Na\ \times\frac{1\ mol\ Na}{22.99\ g\ Na}=  

c)

 2.50 g Na ×22.99 g Na1 mol Na=2.50\ g\ Na\ \times\frac{22.99\ g\ Na}{1\ mol\ Na}=  

d)

 2.50 g Na ×1 g Na 22.99 mol Na=2.50\ g\ Na\ \times\frac{1\ g\ Na\ }{22.99\ mol\ Na}=  

7.

How would you set up the problem if you want to find the mass, in grams, of 0.55 moles of silicon?

a)

 0.55 mol Si × 28.09 g Si1 mol Si = 0.55\ mol\ Si\ \times\ \frac{28.09\ g\ Si}{1\ mol\ Si}\ =\   

b)

 0.55 mol Si ×1 g Si 28.09 mol Si=0.55\ mol\ Si\ \times\frac{1\ g\ Si\ }{28.09\ mol\ Si}=  

c)

 0.55 mol Si ×28.09 mol Si1 g Si=0.55\ mol\ Si\ \times\frac{28.09\ mol\ Si}{1\ g\ Si}=  

d)

 0.55 mol Si ×1 mol Si28.09 g Si=0.55\ mol\ Si\ \times\frac{1\ mol\ Si}{28.09\ g\ Si}=  

8.

What is the mass, in grams, of 3.33 mol of aluminum?

a)

89.8 g Al

b)

90. g Al

c)

0.123 g Al

d)

0.12 g Al

9.

How many moles are in a sample of 145.0 g of KBr?

a)

17,255 mol KBr

b)

17,260 mol KBr

c)

1.22 mol KBr

d)

1.218 mol KBr

10.

How would you set up the problem if you have 3.80 moles of calcium (Ca), and you are trying to determine how many atoms of calcium you have?

a)

 3.80 mol Ca ×40.08 g Ca1 mol Ca=3.80\ mol\ Ca\ \times\frac{40.08\ g\ Ca}{1\ mol\ Ca}=  

b)

 3.80 mol Ca ×6.022 x 1023 atoms Ca1 mol Ca=3.80\ mol\ Ca\ \times\frac{6.022\ x\ 10^{23\ }atoms\ Ca}{1\ mol\ Ca}=  

c)

 3.80 mol Ca ×1 g Ca40.08 mol Ca=3.80\ mol\ Ca\ \times\frac{1\ g\ Ca}{40.08\ mol\ Ca}=  

d)

 3.80 mol Ca ×1 atoms Ca6.022 x 1023 mol Ca=3.80\ mol\ Ca\ \times\frac{1\ atoms\ Ca}{6.022\ x\ 10^{23}\ mol\ Ca}=  

11.

How would you set up a problem if you had 2.12x1024 molecules of water (H2O) and wanted to figure out how many moles of water you had?

a)

2.12×1024molecules H2O ×1 mol H2O18.02 molecules H2O=2.12\times10^{24^{ }}molecules\ H_2O\ \times\frac{1\ mol\ H_2O}{18.02\ molecules\ H_2O}=

b)

2.12×1024molecules H2O ×18.02 mol H2O1 molecules H2O=2.12\times10^{24^{ }}molecules\ H_2O\ \times\frac{18.02\ mol\ H_2O}{1\ molecules\ H_2O}=

c)

2.12×1024molecules H2O ×6.022 ×1023 mol H2O1 molecules H2O=2.12\times10^{24^{ }}molecules\ H_2O\ \times\frac{6.022\ \times10^{23}\ mol\ H_2O}{1\ molecules\ H_2O}=

d)

2.12×1024molecules H2O ×1 mol H2O6.022×1023 molecules H2O=2.12\times10^{24^{ }}molecules\ H_2O\ \times\frac{1\ mol\ H_2O}{6.022\times10^{23}\ molecules\ H_2O}=

12.

If you're converting between grams and moles you need to use:

a)

1 mole = 6.022x1023 things

b)

the metric prefix chart

c)

molar mass

d)

the atomic number

13.

If you want to convert between atoms and moles you need to use:

a)

1 mole = 6.022x1023 things

b)

the molar mass

c)

the metric prefix chart

d)

the atomic number