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Worksheets9A - MOMENTS
Total questions: 24
Worksheet time: 43mins
Unit of force is .........
Meter
Centimeter
Newton
Kilogram
Moment (Nm) =
Force (N) x distance (m)
Energy (J) x distance (m)
Force (N) / distance (m)
Force (kg) x distance (cm)
What do we call the turning effect of a force?
Momentum
Moment
Pivot
Angular force
What is the moment acting on the seesaw?
1.6 Nm
10 Nm
16 N
4 Nm
A wrench is used to tighten a nut. A 15N perpendicular force is applied 50cm away from the axis of rotation. What is the moment applied to the wrench?
7.5 Nm
1.5 Nm
750 Nm
0.3 Nm
What is the size of the moment shown by the black arrow?
30 Nm
36 Nm
40 Nm
60 Nm
A nut can be loosened more easily with
a short spanner because a larger turning effect can be produced.
a long spanner because a larger turning effect can be produced.
a long spanner because a larger force can be produced.
a short spanner because a larger force can be produced.
What is the anticlockwise moment acting on this crane?
80,000 Nm - moment of the load
100,000 Nm - moment of the load
100,000 Nm - moment of the concrete blocks
200,000 Nm - moment of the concrete blocks
State the principle of moments.
When a system is in equilibrium, the sum of the total clockwise moment is equal to the sum of the total anti-clockwise moment about the same pivot.
When a system is in equilibrium, the sum of the total clockwise moment is greater the sum of the total anti-clockwise moment about the same pivot.
When a system is in equilibrium, the sum of the total clockwise moment is less than the sum of the total anti-clockwise moment about the same pivot.
When a system is in equilibrium, the sum of the total clockwise moment is greater than the sum of the total anti-clockwise moment about different pivots.
A boy of weight 600N sits on the see-saw as shown at a distance of 1.5m from the pivot. What is the force F required at the other end to balance the see-saw?
450 N
350 N
4.5 N
200 N
Two masses of mass 10.0 and 6.0 kg are hung at the ends of a weightless rod. If the 6.0 kg mass is 4.0 m away from the pivot, how far away from the pivot is the 10.0 kg mass if the system is not rotating?
0.42 m
2.4 m
4.8 m
4.2 m
A seesaw is unbalanced with two people of different masses sitting equal distances from the center. Which of the following may result in equilibrium?
The larger person moving further away from the center.
Moving the smaller person closer to the center.
Moving the smaller person further from the center.
Making the larger person do nothing.
The figure below shows a man lifting a heavy rock using a steel bar. He pushes downwards on the end of the bar with a force F.
Which pivot position allows the force F to be as small as possible?
A
B
C
D
What is the resultant turning moment and its direction?
20 Nm anticlockwise
300 Nm anticlockwise
320 Nm clockwise
620 N clockwise
At what distance from the pivot should a 2 N load be placed so that the see-saw does not rotate?
0.2m
0.5m
0.45m
0.42m
If the turning forces are balanced, what is the weight of the object on the right?
4.8N
96N
120N
6N
A beam lies on a pivot as shown. If F1 = F2 the beam will..
turn clockwise
turn anti-clockwise
not turn
can not be determined
Considering moment about the pivot, the given system of forces will....
Not rotate
Can not be determined
start turning clockwise
start turning anti-clock wise
The uniform rod shown is in equilibrium. What is the upward reaction force on support A?
44 N
33 N
22 N
11 N
The rod shown is in equilibrium on two supports as shown and its weight (W=120N) is marked on the diagram. What is the value of the upward reaction force on support B?
20 N
30 N
60 N
90 N
CHALLENGE QUESTION 1: The diagram shows a beam. Three weights are hung on it as shown.
At which point should we place a load of 2 N so that the beam does not rotate?
A
B
C
D
CHALLENGE QUESTION 2: Assuming the system is in equilibrium, calculate the missing distance d
3.4 m
2.8 m
4.4 m
1.6 m
